
Understanding Limits and Indeterminate Forms

Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Easy
Standards-aligned

Lucas Foster
Used 1+ times
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the main goal when finding the limit as x approaches 0 for the given function?
To find the exact value of the function at x = 0
To find the maximum value of the function
To determine the value the function approaches from both sides of 0
To calculate the derivative of the function at x = 0
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why does direct substitution in the given limit problem result in an indeterminate form?
Because it results in a division by zero
Because the function is undefined for all x
Because it results in a negative value
Because the function is continuous at x = 0
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the graph of the function indicate about the limit as x approaches 0?
The limit is different from the left and right
The limit exists and is the same from both sides
The function value is undefined at x = 0
The limit does not exist
Tags
CCSS.HSF.IF.A.2
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the purpose of rationalizing the numerator in the limit problem?
To make the function continuous
To eliminate the indeterminate form
To find the derivative
To simplify the denominator
Tags
CCSS.HSA.APR.D.6
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the conjugate of the numerator in the given function?
Square root of (x + 1) - 1
Square root of (x + 1) + 1
1 - square root of (x + 1)
x + 1
Tags
CCSS.HSA.APR.D.6
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the terms in the numerator after multiplying by the conjugate?
They simplify to a single term
They cancel each other out
They remain unchanged
They become more complex
Tags
CCSS.HSA.APR.D.6
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
After simplifying, what common factor is found in both the numerator and the denominator?
1
x
Square root of x + 1
x + 1
Tags
CCSS.HSF.IF.A.2
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