
Understanding Limits Involving Trigonometric Functions

Interactive Video
•
Mathematics
•
9th - 12th Grade
•
Hard
+1
Standards-aligned

Jackson Turner
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What are the three main approaches to finding limits?
Numerical, Graphical, Analytical
Visual, Logical, Empirical
Algebraic, Geometric, Statistical
Theoretical, Practical, Experimental
Tags
CCSS.HSF-IF.C.7D
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
According to the informal definition, when does the limit of f(x) as x approaches c equal L?
When f(x) is greater than L
When f(x) values are close to L for x near c
When f(x) is undefined at c
When f(x) is always equal to L
Tags
CCSS.HSF-IF.C.7D
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is NOT a reason for the non-existence of a limit?
Function is continuous at c
Function oscillates between fixed values
Function increases or decreases without bound
Function approaches different values from left and right
Tags
CCSS.HSF.IF.A.2
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the limit of sin(x) as x approaches π/6?
π/6
1
1/2
0
Tags
CCSS.8.EE.C.7A
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why can direct substitution be used to find the limit of sin(x) as x approaches π/6?
Because sin(x) is discontinuous at π/6
Because sin(x) is undefined at π/6
Because sin(x) is smooth and continuous around π/6
Because sin(x) is a constant function
Tags
CCSS.HSF.IF.A.2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the limit of tan(x) as x approaches π/2?
It approaches zero
It approaches infinity
It does not exist
It approaches a constant value
Tags
CCSS.8.EE.C.7A
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why does the limit of tan(x) not exist as x approaches π/2?
Because tan(x) is continuous at π/2
Because tan(x) approaches different values from left and right
Because tan(x) is a constant function
Because tan(x) is zero at π/2
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