Spring-Mass System Dynamics

The video tutorial explains a physics problem involving a spring with a known spring constant and a mass placed on it. The spring is compressed, and the task is to find the velocity of the mass when the spring is released. The principle of energy conservation is used, equating the total energy in two states. Known variables are identified, and units are converted to ensure consistency. The problem is broken down into initial and final states, simplifying the energy equation to solve for the launch velocity. The final calculation yields a velocity of approximately 1.43 meters per second.

What is the spring constant used in the problem?

• 6 N/m

• 8 N/m

• 4 N/m

• 2 N/m

What principle is used to solve the problem of the spring and mass?

• Newton's First Law

• Conservation of Energy

• Conservation of Momentum

• Hooke's Law

What is the mass of the object placed on the spring?

• 5 grams

• 10 grams

• 15 grams

• 20 grams

What is the initial compression of the spring in meters?

• 0.2 meters

• 0.1 meters

• 0.15 meters

• 0.05 meters

What is the gravitational acceleration used in the calculations?

• 8.9 m/s²

• 10.8 m/s²

• 9.8 m/s²

• 11.8 m/s²

Which term in the energy equation is zero in the initial state?

• Kinetic energy

• Elastic potential energy

• Gravitational potential energy

• All of the above

What is the final velocity of the mass when the spring is uncompressed?

• 3.43 m/s

• 2.43 m/s

• 1.43 m/s

• 0.43 m/s

What is the unit of the spring constant?

• Newton

• Kilogram

• Meter per second

• Newton per meter

What is the final height of the mass in meters?

• 0.2 meters

• 0.15 meters

• 0.1 meters

• 0.05 meters

What is the formula used to calculate the launch velocity?

• v = √(2gh)

• v = √(k/m)

• v = √(kΔx²/m - 2gh)

• v = √(2kΔx/m)