What is the main challenge when factoring quadratics with a leading coefficient not equal to 1?
3 Easy Quadratics to Factor when a is not 1

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Mathematics, Science
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11th Grade - University
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Hard
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7 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
There are no prime numbers involved.
The process is always complex.
It can be tricky but some problems are basic.
The quadratic cannot be factored.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
When factoring 3x^2 - 4x + 1, why are the factors limited?
Because the quadratic is already in simplest form.
Because the middle term is positive.
Because 4 is a composite number.
Because 3 and 1 are both prime numbers.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the quadratic 3x^2 - 4x + 1, what are the signs of the factors?
Cannot be determined
Both positive
Both negative
One positive, one negative
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
For the quadratic 2x^2 + 5x + 3, what is the correct arrangement of factors to achieve the middle term?
2x + 1 and x + 3
x + 3 and 2x + 1
2x + 3 and x + 1
3x + 1 and 2x + 1
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why must both factors be positive in the quadratic 2x^2 + 5x + 3?
Because both the last and middle terms are positive.
Because the leading coefficient is prime.
Because the middle term is negative.
Because the last term is negative.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In the quadratic 7t^2 + 2t - 5, why is one factor positive and one negative?
Because the middle term is negative.
Because the last term is negative.
Because the leading coefficient is composite.
Because both terms are positive.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What determines the sign of the larger product in the quadratic 7t^2 + 2t - 5?
The sign of the middle term
The size of the leading coefficient
The sign of the last term
The presence of prime numbers
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