Solving a quadratic using the square root method when there are no solutions

The video tutorial explains solving the equation y = X^2 + 3/4 by setting y to zero and isolating X. It highlights that taking the square root of a negative number results in no real solutions, concluding that there are no X intercepts under the real number system.

What is the first step in solving the equation y = X^2 + 3/4?

• Add 3/4 to both sides

• Set Y equal to zero

• Multiply both sides by 2

• Set X equal to zero

After setting y to zero, what operation is performed next?

• Subtract 3/4 from both sides

• Multiply by 3/4

• Add 3/4 to both sides

• Divide by 3/4

Why can't we find real solutions for X in the equation X^2 = -3/4?

• Because the square root of a negative number is not real

• Because X is already isolated

• Because the equation is not quadratic

• Because 3/4 is too small

What does the absence of real solutions imply about the graph of the equation?

• It is a circle

• It is a straight line

• It has no X-intercepts

• It has no Y-intercepts

Under which number system does the equation have no X-intercepts?

• Integer number system

• Real number system

• Imaginary number system

• Complex number system