What is the main goal of the problem introduced in the first section?

Conversions in Chemistry: Moles and Grams

Interactive Video
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Chemistry
•
9th - 10th Grade
•
Hard

Patricia Brown
FREE Resource
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
To find the number of atoms in a molecule
To convert moles to grams
To determine the number of molecules in a given mass of calcium carbonate
To calculate the mass of calcium carbonate
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which conversion factor is used first when converting from grams to moles?
1 mole of calcium carbonate equals 100.09 grams
1 gram of calcium carbonate equals 6.02 x 10^23 molecules
1 mole of calcium carbonate equals 50 grams
1 mole of calcium carbonate equals 6.02 x 10^23 molecules
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What must be on the bottom of the fraction when converting from grams to moles?
Atoms of calcium carbonate
Molecules of calcium carbonate
Grams of calcium carbonate
Moles of calcium carbonate
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the second conversion factor used to convert moles to molecules?
1 mole of calcium carbonate equals 100.09 grams
1 mole of calcium carbonate equals 6.02 x 10^23 molecules
1 gram of calcium carbonate equals 6.02 x 10^23 molecules
1 mole of calcium carbonate equals 50 grams
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How do you represent 6.02 x 10^23 in calculator notation?
6.02x10^23
6.02/23
6.02E23
6.02*23
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the final result of the conversion from grams to molecules?
1.80 x 10^23 molecules
2.00 x 10^23 molecules
1.00 x 10^23 molecules
3.00 x 10^23 molecules
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the new problem introduced in the last section?
Converting moles to atoms
Converting atoms to grams
Converting grams to atoms
Converting molecules to grams
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