Genetics of Color Blindness

The video tutorial explains sex chromosomes and uses a genetic example involving a colorblind male and a heterozygous normal female. It covers determining the genotypes of the parents, the mating process, and the use of a Punnett square to calculate probabilities of genetic outcomes, such as the likelihood of having a colorblind child or a normal child.

What is the genetic condition of the male in the example?

• Heterozygous recessive

• Homozygous dominant

• Hemizygous recessive

• Heterozygous normal

Which chromosome carries the gene for color blindness in males?

• Y chromosome

• Both X and Y chromosomes

• X chromosome

• Neither X nor Y chromosomes

What is the genetic makeup of a heterozygous normal female?

• XX with both carrying colorblind gene

• XY with one carrying normal vision gene

• XX with one normal and one colorblind gene

• YY with both carrying normal vision gene

What is the dominant gene for color vision represented by?

• Lowercase blue c

• Uppercase red C

• Uppercase blue C

• Lowercase red c

During meiosis, what types of cells are produced by the colorblind male?

• One type of X and one type of Y cell

• Two types of Y cells

• Two types of X cells

• Two identical X cells

What is the probability that a child will be colorblind, regardless of gender?

• 75%

• 50%

• 25%

• 100%

If the child is male, what is the probability that he will be colorblind?

• 10%

• 75%

• 25%

• 50%

If the child is female, what is the probability that she will be normal?

• 10%

• 25%

• 50%

• 75%

What is the probability that both children will be normal if the couple has two children?

• 25%

• 10%

• 75%

• 50%

What is the probability that a child will be both male and colorblind?

• 10%

• 25%

• 75%

• 50%