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Lewis Structures and Valence Electrons

Lewis Structures and Valence Electrons

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Practice Problem

Hard

Created by

Ethan Morris

FREE Resource

The video tutorial explains how to draw the Lewis structure for bromoethane (C2H5Br). It begins by counting the valence electrons of carbon, hydrogen, and bromine, totaling 20. The tutorial then guides viewers through placing the atoms and forming bonds, ensuring each atom satisfies the octet rule. The video also discusses the 3D structure of the molecule, noting that the position of bromine can vary without changing the molecule's identity. Finally, it presents an alternative representation of the Lewis structure, omitting lone pairs on bromine.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total number of valence electrons in bromoethane (C2H5Br)?

24

18

20

22

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the Lewis structure for bromoethane?

Oxygen

Carbon

Bromine

Hydrogen

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why are hydrogen atoms placed on the outside of the Lewis structure?

They are larger in size.

They have more valence electrons.

They can only form one bond.

They have the highest electronegativity.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is formed when a pair of electrons is placed between two atoms?

A free radical

A chemical bond

A lone pair

An ionic bond

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons does each hydrogen atom need to be stable?

1

2

4

8

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the octet rule in the Lewis structure?

It limits the number of bonds an atom can form.

It ensures atoms have eight electrons in their outer shell.

It determines the shape of the molecule.

It specifies the number of lone pairs.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Does the position of bromine affect the identity of the bromoethane molecule?

Yes, it changes the molecule.

No, it remains the same molecule.

Yes, it alters the chemical properties.

No, but it changes the molecular weight.

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