Molar Mass and Chemical Formulas

Molar Mass and Chemical Formulas

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Lucas Foster

FREE Resource

The video tutorial explains how to calculate the molar mass of nickel(II) nitrate hexahydrate, Ni(NO3)2.6H2O. It begins by identifying the molar masses of nickel, nitrogen, and oxygen from the periodic table. The tutorial then demonstrates how to multiply the molar mass of oxygen by three, as there are three oxygen atoms in the compound. Next, it adds the molar mass of six water molecules, considering the molar masses of hydrogen and oxygen. The final molar mass of the compound is calculated to be 228.82 grams per mole. The video concludes by noting that different periodic tables may yield slightly different results.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the chemical formula for nickel(II) nitrate hexahydrate?

Ni(NO3)2.5H2O

Ni(NO2)2.6H2O

Ni(NO3)3.6H2O

Ni(NO3)2.6H2O

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of nickel used in the calculation?

58.69 grams per mole

14.01 grams per mole

16.00 grams per mole

1.01 grams per mole

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many oxygen atoms are present in the nitrate component of Ni(NO3)2.6H2O?

Two

Six

Four

Three

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the molar mass of hydrogen used in the calculation of water molecules?

58.69 grams per mole

1.01 grams per mole

14.01 grams per mole

16.00 grams per mole

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many water molecules are associated with each formula unit of Ni(NO3)2.6H2O?

Six

Two

Three

Four

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final calculated molar mass of Ni(NO3)2.6H2O?

228.82 grams per mole

200.00 grams per mole

250.00 grams per mole

180.00 grams per mole

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why might the calculated molar mass differ slightly when using different periodic tables?

Due to different chemical reactions

Due to incorrect chemical formulas

Due to rounding differences

Due to changes in temperature