Oxidation Numbers in SF4

Oxidation Numbers in SF4

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Olivia Brooks

FREE Resource

The video tutorial explains how to determine the oxidation numbers of elements in sulfur tetrafluoride (SF4). It begins by identifying the oxidation number of fluorine as -1 and uses the rule that the sum of oxidation numbers in a neutral compound must be zero. By applying this rule, the oxidation number of sulfur is calculated to be +4. The video concludes with a recap of the process used to find these oxidation numbers.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the central element in SF4?

Fluorine

Sulfur

Nitrogen

Oxygen

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many fluorine atoms are present in SF4?

2

3

4

5

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the oxidation number of fluorine in SF4?

-1

0

+1

+2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why must the oxidation numbers in a neutral compound add up to zero?

To ensure the compound is stable

To balance the chemical equation

Because there is no overall charge

Because the compound is charged

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the oxidation number of sulfur in SF4?

-4

+4

+2

0

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the total oxidation number of all fluorine atoms in SF4?

-4

+4

0

-2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of finding oxidation numbers in a compound?

To determine the molecular weight

To identify the type of bond

To understand electron transfer

To calculate the melting point