Lewis Structures and Octet Rule

Lewis Structures and Octet Rule

Assessment

Interactive Video

Chemistry

9th - 10th Grade

Hard

Created by

Jackson Turner

FREE Resource

The video tutorial explains the process of drawing the Lewis structure for Carbonyl Dichloride (Cl2CO). It begins by counting the valence electrons for each atom: Chlorine, Carbon, and Oxygen, totaling 24. The structure is built by placing Carbon in the center, with Chlorines on either side and Oxygen on top. Initial bonds are formed using 6 electrons, and the remaining electrons are distributed to satisfy the octet rule. A double bond is formed between Carbon and Oxygen to ensure all atoms have complete octets. The tutorial concludes with a review of the completed Lewis structure.

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6 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many valence electrons are there in total for Cl2CO?

18

24

28

30

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which atom is placed at the center of the Cl2CO Lewis structure?

Carbon

Oxygen

Chlorine

Hydrogen

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many electrons are initially used to form bonds between the atoms in Cl2CO?

4

10

8

6

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the issue with the initial electron distribution in Cl2CO?

Oxygen has too many electrons

Chlorine atoms are not bonded

Carbon does not have a full octet

There are extra electrons

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the octet rule satisfied for Carbon in Cl2CO?

By adding more electrons to Chlorine

By forming a double bond with Oxygen

By removing electrons from Oxygen

By rearranging Chlorine atoms

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final structure of Cl2CO after adjustments?

Chlorine forms a double bond with Carbon

All atoms have complete octets

Carbon forms a triple bond with Oxygen

All atoms have incomplete octets