Methods for Finding Minimum Values

Methods for Finding Minimum Values

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Thomas White

FREE Resource

The video tutorial addresses a problem from the British Math Olympiad 2006, presenting two methods to solve it. The first method involves using polar coordinates and trigonometric identities to simplify the equation and find the minimum value of x^2 + y^2. The second method employs algebraic manipulation, rewriting the equation in terms of x^2 + y^2 and xy, and using inequalities to determine the minimum value. Both methods conclude that the minimum value of x^2 + y^2 is 4.

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15 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What year was the British Math Olympiad problem discussed in the video?

2004

2006

2007

2005

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the first method, which mathematical concept is used to relate x^2 + y^2 to trigonometric identities?

Complex Numbers

Polar Coordinates

Pythagorean Theorem

Matrix Algebra

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What substitution is made for x and y in the first method?

x = Rtan(θ), y = Rcot(θ)

x = Rsec(θ), y = Rcsc(θ)

x = Rsin(θ), y = Rcos(θ)

x = Rcos(θ), y = Rsin(θ)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of using polar coordinates in the first method?

To eliminate variables

To simplify the trigonometric expression

To find the maximum value

To convert to Cartesian coordinates

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric identity is used to simplify the expression in the first method?

sin(2θ) = 2sin(θ)cos(θ)

cos(2θ) = cos^2(θ) - sin^2(θ)

tan^2(θ) + 1 = sec^2(θ)

sin^2(θ) + cos^2(θ) = 1

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the inequality sin(4θ) ≤ 1 in the first method?

It eliminates variables

It simplifies the equation

It helps find the minimum value

It helps find the maximum value

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the minimum value of R^2 found in the first method?

3

4

5

2

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