Evaluating Function Values on Graphs

The video tutorial explains how to evaluate the function f at x=6 using a graph, determining that f(6) equals 2 by locating the y-coordinate at x=6. It then addresses solving for x when f(x) equals 1, identifying that x=3 satisfies this condition by drawing a horizontal line at y=1 and finding where it intersects the graph.

What is the main task in part a of the problem?

• Evaluate f(6)

• Find the x-coordinate when f(x) = 1

• Calculate the area under the curve

• Determine the slope of the graph

What does f(6) represent in the context of the graph?

• The slope of the tangent at x = 6

• The area under the graph from 0 to 6

• The y-coordinate when x = 6

• The x-coordinate when y = 6

What is the first step in evaluating f(6) on the graph?

• Find the slope of the graph

• Draw a vertical line at x = 0

• Calculate the area under the curve

• Locate x = 6 on the x-axis

Where should you look on the graph to find f(6)?

• Where y = 6

• Where x = 6

• Where x = 0

• At the origin

What is the significance of the point where x = 6 on the graph?

• It is the maximum point of the graph

• It is where the graph intersects the y-axis

• It is where you find f(6)

• It is the minimum point of the graph

What is the value of f(6) according to the graph?

• 1

• 3

• 0

• 2

What does the y-coordinate represent when x = 6?

• The value of f(6)

• The area under the curve

• The slope of the graph

• The x-intercept

What is the goal of part b of the problem?

• Find the x-coordinate when f(x) = 1

• Evaluate f(6)

• Determine the slope of the graph

• Calculate the area under the curve

What should you draw to find where f(x) = 1?

• A tangent line at x = 1

• A diagonal line through the origin

• A horizontal line at y = 1

• A vertical line at x = 1

What is the purpose of drawing a horizontal line at y = 1?

• To calculate the area under the curve

• To locate where f(x) = 1

• To determine the slope

• To find the x-intercept