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WorksheetsChapter 4 - STA404
Total questions: 37
Worksheet time: 1hrs 27mins
Is the mean height of female college students greater than 5.5 feet?
Paired t-test. Students heights can be measured against females of similar backgrounds.
1-sample t-test. Test whether the mean of a single sample is equal to the target value of 5.5 feet.
2-sample t-test. Test whether the heights of female college students is higher than their high school heights.
Use a z-test by finding the mean height and standard deviation of the sample of college females' heights.
Does the mean height of female college students significantly differ from the mean height of male college students?
Paired t-test. Test whether the difference of the means of one male paired with one female is equal to 0.
2-sample t-test. Test whether the mean height of female college students is different than the mean height of male college students.
1-sample t-test. Test whether the mean of randomly assigned pairs of female and male students is greater than the mean of the average of males and females.
z-test. Use proportions in place of means to run a one sample z-test for males and females and compare averages.
I run a paired t-test for 15 sets of first grade twins reading abilities if one twin used a computer program tutor and the other did not, and get a p-value of 0.02, what does this mean for a significance level of 0.05?
Reject the null hypothesis. There is evidence at the 0.05 level that the computer program tutor is more effective at raising reading scores.
Fail to reject the null hypothesis. There is no evidence at the 0.05 level that the computer program tutor is more effective at raising reading scores.
Accept the null hypothesis. There is evidence at the 0.05 level that the computer program tutor is more effective at raising reading scores.
This was not the proper use of a paired t-test; no conclusions can be drawn from this test.
We use a paired t-test for 18 students in the Bethel AP statistics class and 18 students in the Kecoughtan class to see if one teacher has higher scores on the AP exam than another.We get a p-value of 0.14. What should we conclude?
Reject the null hypothesis. There is evidence at the 0.05 level that the one teacher has higher scores than another.
Fail to reject the null hypothesis. There is no evidence at the 0.05 level that one teacher has higher scores than another.
Accept the null hypothesis. There is evidence at the 0.05 level that one teacher's scores are higher than the other teacher's.
This was not the proper use of a paired t-test; no conclusions can be drawn from this test.
A manufacturer of gloves wants to determine if a special type of wool gloves lasts longer than the cotton gloves they manufacture. He makes pairs of gloves in which the left hand is cotton and the right hand is wool. We sample 24 women who wear these pairs of gloves, then use a paired t-test to find the mean of the differences in wear between the right glove and left glove; we get a p-value of 0.043. At the 0.05 level, what should we conclude?
Reject the null. There is evidence at the 0.05 significance level that the wool gloves lasts longer than the cotton glove.
Fail to reject the null. There is evidence at the 0.05 significance level that the wool glove lasts longer than the cotton glove.
Fail to reject the null. There is no evidence at the 0.05 significance level that the wool glove lasts longer than the cotton glove.
We cannot conclude anything because a paired t-test was not the appropriate test to run for this sample.
A researcher gave one group of people an active drug and gave a different group of people an inactive placebo, then compare the blood pressures between the groups. Which test should he run to determine the efficacy of the active drug?
Paired t-test. Since there is a group with the active drug and another with the inactive drug, he may pair the two two groups if the sample sizes are the same.
2-sample t-test. Since the blood pressures were taken for patients in sample 1 and different patients in sample 2, use a two-sample t-test to see if the results are statistically significant.
1-sample t-test. The researcher should compare the mean of the first sample of patients to the mean of the second sample of patients.
2-sample z-test. There is no natural pairing between the two samples, so the researcher must use a proportions test.
With p-value approach, the H0 will rejected if p-value is ________ than α
≤
≥
<
Ha: p > .21
Ha: p= .21
Ha: p= .21
Ha: p< .21
Would I use the z-test or t-test and why?
Z-test, n > 30
T-test, n < 30
Would I use the z-test or t-test and why?
Z-test, n > 30
T-test, n < 30
Would I use the z-test or t-test?
Z-test
T-test
Would I use the z-test or t-test?
Z-test
T-test
Use the z-table to calculate the critical value.
zo = 1.28
zo = 1.03
Use the z-table to calculate the critical value.
zo = 1.03
zo = -1.28
Use the z-table to calculate the critical values.
zo = -1.96 and 1.96
zo = -1.45 and 1.45
