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Unit 4 Practice Quiz (Gravitation/Coulomb's Law)

Total questions: 55

Worksheet time: 28mins

Name
Class
Date
1.

Which number is written in scientific notation?

a)

 7.35 × 10227.35\ \times\ 10^{22}  

b)

 7350000000000000000000073500000000000000000000  

2.

Which number is not written in scientific notation?

a)

 1.74 ×1061.74\ \times10^6  

b)

 17400001740000  

3.

What is a force?

a)

any push or pull

b)

a way to write very big or very small numbers

c)

the Italian scientist whose famous experiment included dropping two cannonballs from the Leaning Tower of Pisa

d)

the English scientist most famous for his three laws of motion

4.

Which is gravitational force (gravity)?

a)

the force that causes something to fall to the ground or to be attracted to another planet

b)

the force between two charged objects

5.

Which symbol represents gravitational force (gravity)?

a)
b)
6.

Which model correctly shows the forces acting on the astronaut and the moon?

a)
b)
7.

Mr. Pham weighs 210 pounds (yes, really), which is the same thing as 95.25 kilograms.


What does the 95.25 kilograms represent?

a)

Mr. Pham's mass

b)

Mr. Pham's length

c)

Mr. Pham's volume

d)

Mr. Pham's temperature

8.

What is the abbreviation (short form) for the word kilogram?

a)

kg

b)

mg

c)

g

d)

mL

9.

Which equation represents Newton's Law of Gravitation?

a)
b)
10.

What does the word magnitude mean?

a)

size

b)

color

c)

temperature

11.

What are the units used to measure force?

a)

meters

b)

liters

c)

grams

d)

Coulombs

e)

Newtons

12.

The units used to measure force are Newtons.


What is the abbreviation (short form) for Newtons?

a)

gg

b)

ll

c)

mm

d)

KK

e)

NN

13.

What does Newton's 1st Law of Motion (also known as the law of inertia) say?

a)

"An object at rest stays at rest, and an object in motion stays in motion - unless acted upon by an external force."

b)

"For every action, there's an equal and opposite reaction."

c)

 F = m×aF\ =\ m\times a  

where:

 FF  represents force.
 mm  represents mass.
 aa  represents acceleration.

14.

What does Newton's 3rd Law of Motion say?

a)

"An object at rest stays at rest, and an object in motion stays in motion - unless acted upon by an external force."

b)

"For every action, there's an equal and opposite reaction."

c)

 F = m×aF\ =\ m\times a  

where:

 FF  represents force.
 mm  represents mass.
 aa  represents acceleration.

15.

An astronaut stands on the moon.

Which equation is the correct one for calculating the gravitational force between the astronaut and moon?

a)
b)
16.

Click Zoom In to see the notes.

According to these notes, what is the value of the universal gravitational constant ( GG )?

a)

 6.67 × 10116.67\ \times\ 10^{-11}  

b)

 8.99 ×1098.99\ \times10^9  

17.

An astronaut stands on the moon.

•The astronaut ( m1m_1 ) has a mass of  100 kg100\ kg .
•The moon ( m2m_2 ) has a mass of  7.35 × 1022 kg7.35\ \times\ 10^{22}\ kg .
•The distance ( rr ) between the astronaut and moon is  1.74 × 106 m1.74\ \times\ 10^6\ m .
•The universal gravitational constant ( GG ) is  6.67 ×10116.67\ \times10^{-11} .

The equation for Newton's Law of Gravitation is:  Fg=G ×m1 × m2r2F_g=\frac{G\ \times m_1\ \times\ m_2}{r^2}  

What is the correct way to plug all of these numbers into the equation?

a)

 Fg = (6.67 × 1011) × 100 ×(7.35 ×1022)(1.74 ×106)2F_g\ =\ \frac{\left(6.67\ \times\ 10^{-11}\right)\ \times\ 100\ \times\left(7.35\ \times10^{22}\right)}{\left(1.74\ \times10^6\right)^2}  

b)

 Fg = (1.74 ×106) × 100 ×(7.35 ×1022)(6.67 × 1011)2F_g\ =\ \frac{\left(1.74\ \times10^6\right)\ \times\ 100\ \times\left(7.35\ \times10^{22}\right)}{\left(6.67\ \times\ 10^{-11}\right)^2}  

18.

An astronaut stands on the moon.

•The astronaut ( m1m_1 ) has a mass of  100 kg100\ kg .
•The moon ( m2m_2 ) has a mass of  7.35 × 1022 kg7.35\ \times\ 10^{22}\ kg .
•The distance ( rr ) between the astronaut and moon is  1.74 × 106 m1.74\ \times\ 10^6\ m .
•The universal gravitational constant ( GG  ) is  6.67 ×10116.67\ \times10^{-11} .

The equation for Newton's Law of Gravitation is:  Fg =G ×m1×m2r2F_{g\ }=\frac{G\ \times m_1\times m_2}{r^2}  

Plugging all of these numbers into the equation gives this setup:
 Fg = (6.67 × 1011) × 100 ×(7.35 ×1022)(1.74 ×106)2F_g\ =\ \frac{\left(6.67\ \times\ 10^{-11}\right)\ \times\ 100\ \times\left(7.35\ \times10^{22}\right)}{\left(1.74\ \times10^6\right)^2}  

Enter this same setup into the Desmos scientific calculator (desmos.com/scientific) to calculate the answer for  FgF_g .

a)

 Fg = 161.93 NF_g\ =\ 161.93\ N  

b)

 Fg = 261.93 NF_g\ =\ 261.93\ N  

c)

 Fg = 361.93 NF_g\ =\ 361.93\ N  

d)

 Fg = 461.93 NF_g\ =\ 461.93\ N  

19.

When the astronaut jumps up and down on the moon, it takes more time for her to come back down on her feet (compared to when she's on Earth).


The reason behind this is because the gravitational force she feels on the moon is _____ the gravitational force she feels on the Earth.

a)

less than

b)

greater than

c)

equal to

20.

The moon has a mass of  7.35 × 10227.35\ \times\ 10^{22}  kg.

The Earth has a mass of  5.97 ×10245.97\ \times10^{24}  kg.

 The equation for Newton's Law of Gravitation is:  Fg = G ×m1×m2r2F_g\ =\ \frac{G\ \times m_1\times m_2}{r^2}   

Use the information above to answer this question:
Why does an astronaut feel a smaller gravitational force on the moon than on the Earth?

Hint: Think about the mathematical relationships in the equation.

a)

Since the moon has a smaller mass then the Earth, the moon also has smaller gravitational force ( FgF_g ). This is because an object's mass and its  FgF_g are directly proportional to each other in the equation for Newton's Law of Gravitation.

b)

Since the moon has a smaller mass then the Earth, the moon also has smaller gravitational force ( F_g ). This is because an object's mass and its  F_g are inversely proportional to each other in the equation for Newton's Law of Gravitation.

21.

Which is electrostatic force?

a)

the force that causes something to fall to the ground or to be attracted to another planet

b)

the force between two charged objects

22.

Which symbol represents electrostatic force?

a)
b)
23.

Which model correctly shows the forces acting on the two charged hanging balls?

a)
b)
24.

Which equation represents Coulomb's Law?

a)
b)
25.

There are two hanging balls.

The balls are oppositely-charged.

This means one ball is positive (+), and the other is negative (-).

Which equation is the correct one for calculating the electrostatic force between the balls?

a)
b)
26.

What is the distance between the two hanging balls in the image?

a)

 r = 0.5 mr\ =\ 0.5\ m  

b)

 r = 0.05 mr\ =\ 0.05\ m  

c)

 r = 0.005 mr\ =\ 0.005\ m 

d)

 r = 5 mr\ =\ 5\ m  

27.

What are the units used to measure electric charge?


Note: electric charge is not the same thing as electrostatic force.

a)

meters

b)

liters

c)

grams

d)

Coulombs

e)

Newtons

28.

The units used to measure electric charge are Coulombs.


What is the abbreviation (short form) for Coulombs?

a)

kg

b)

mL

c)

km

d)

C

e)

N

29.

Click Zoom In to see the notes.

According to these notes, what is the value of lowercase K (which represents the Coulomb's constant)?

a)

 6.67 × 10116.67\ \times\ 10^{-11} 

b)

 8.99 ×1098.99\ \times10^9  

30.

You have two oppositely-charged hanging balls.

Which equation is the correct one for calculating the electrostatic force between the charged balls?

a)
b)
31.

You have two oppositely-charged hanging balls.

The positive green ball ( q1q_1 ) has a charge of  0.6 C0.6\ C .


The negative orange ball ( q2q_2 ) has a charge of  0.6 C-0.6\ C .


The distance ( rr ) between the balls is  0.5 m0.5\ m .

Coulomb's constant ( kk  ) is  8.99 ×1098.99\ \times10^9 .
Plugging the given information into the equation for Coulomb's Law gives this:
 FE = (8.99 × 109) × (0.6) ×(0.6)(0.5)2F_E\ =\ \frac{\left(8.99\ \times\ 10^9\right)\ \times\ \left(0.6\right)\ \times\left(-0.6\right)}{\left(0.5\right)^2}  

Enter this same setup into the Desmos scientific calculator (desmos.com/scientific) to calculate the answer for  FEF_E .

a)

 FE = 1.29 ×1010 NF_E\ =\ −1.29\ \times10^{10}\ N  

b)

 FE = 2.29 ×1010 NF_E\ =\ −2.29\ \times10^{10}\ N  

c)

 FE = 3.29 ×1010 NF_E\ =\ −3.29\ \times10^{10}\ N  

d)

 FE = 4.29 ×1010 NF_E\ =\ −4.29\ \times10^{10}\ N  

32.

You have two oppositely-charged hanging balls.

•The positive green ball ( q1q_1 ) has a charge of  0.6 C0.6\ C .
•The orange negative ball ( q2q_2 ) has a charge of  0.6 C-0.6\ C .
•The distance ( rr ) between the balls is  0.5 m0.5\ m .
•Coulomb's constant ( kk ) is  8.99 ×1098.99\ \times10^9 .

The equation for Coulomb's Law is:  FE=k ×q1× q2r2F_E=\frac{k\ \times q_1\times\ q_2}{r^2}  

What is the correct way to plug all of these numbers into the equation?

a)

 FE = (8.99 × 109) × 0.6 ×(0.6)(0.5)2F_E\ =\ \frac{\left(8.99\ \times\ 10^9\right)\ \times\ 0.6\ \times\left(-0.6\right)}{\left(0.5\right)^2}  

b)

 FE = 0.5 × 0.6 ×(0.6)(8.99 × 109)2F_E\ =\ \frac{0.5\ \times\ 0.6\ \times\left(-0.6\right)}{\left(8.99\ \times\ 10^9\right)^2}  

33.

If the electrostatic force ( FEF_E ) between two charged objects is a positive number (for example:  1.29 ×10101.29\ \times10^{10} ), does this mean that the charged objects attract or repel each other?

a)

attract (meaning: pull toward each other)

b)

repel (meaning: push each other away)

34.

If the electrostatic force ( FEF_E ) between two charged objects is a negative number (for example:  1.29 ×1010-1.29\ \times10^{10} ), does this mean that the charged objects attract or repel each other?

a)

attract (meaning: pull toward each other)

b)

repel (meaning: push each other away)

35.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

In this equation, is electrostatic force ( FEF_E ) located on the left side or the right side of the equation?

a)

left side

b)

right side

36.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

The electrostatic force ( FEF_E ) is located by itself on the left side of the equation.

In algebra/physics, a number or variable that's by itself always has an invisible number underneath it, resulting in a fraction.

What is the invisible number?

a)

1

b)

0

37.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

The electrostatic force ( FEF_E ) is located by itself on the left side of the equation.

In algebra/physics, a number or variable that's by itself always has an invisible number underneath it, resulting in a fraction.

 FEF_E has an invisible 1 *UNDERNEATH* it.

This means that  FEF_E  is the same thing as...?

a)

 FE1\frac{F_E}{1}  

b)

 1FE\frac{1}{F_E}  

38.

What does "directly proportional" mean?


Be careful:

This is a multi-select answer.

Select all that apply.

a)

as one thing increases,

the other thing also increases

b)

as one thing decreases,

the other thing also decreases

c)

when one thing increases,

the other thing does the decreases instead

d)

when one thing decreases,

the other thing does the increases instead

39.

What does "inversely proportional" mean?


Be careful:

This is a multi-select answer.

Select all that apply.

a)

as one thing increases,

the other thing also increases

b)

as one thing decreases,

the other thing also decreases

c)

when one thing increases,

the other thing does the decreases instead

d)

when one thing decreases,

the other thing does the increases instead

40.

What does the Inverse-Square Law say?


Be careful:

This is a single answer.

a)

as one thing increases,

the other thing also increases

b)

as one thing decreases,

the other thing also decreases

c)

when one thing decreases,

the other thing does the increases instead

d)

when one thing decreases,

the other thing does the increases instead

e)

when one thing decreases

as the square of the other thing

41.

In algebra/physics, a number or variable that's by itself always has an invisible 1 underneath it, resulting in a fraction.

For example:

2 is the same thing as...?

a)

 21\frac{2}{1}  

b)

 12\frac{1}{2}  

42.

In algebra/physics, a number or variable that's by itself always has an invisible 1 underneath it, resulting in a fraction.

For example:

5 is the same thing as...?

a)

 51\frac{5}{1}  

b)

 15\frac{1}{5}  

43.

In algebra/physics, a number or variable that's by itself always has an invisible 1 underneath it, resulting in a fraction.

For example:

10 is the same thing as...?

a)

 101\frac{10}{1}  

b)

 110\frac{1}{10}  

44.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

In this equation, is distance ( rr ) located on the left side or the right side of the equation?

a)

left side

b)

right side

45.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

In this equation, is distance ( rr ) located in the numerator (top) or in the denominator (bottom) of the big fraction?

a)

numerator (top)

b)

denominator (bottom)

46.

In algebra/physics, a number or variable that's by itself always has an invisible 1 underneath it, resulting in a fraction.

This means that  FE F_{E\ }  is the same thing as  FE1\frac{F_E}{1} .

In the fraction  FE1\frac{F_E}{1}  , is  FEF_E  in the numerator (top) or denominator (bottom)?

a)

numerator (top)

b)

denominator (bottom)

47.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

By now, we know that:
 FEF_E  is the same thing as  FE1\frac{F_E}{1}  .
In the fraction  FE1\frac{F_E}{1}  ,  FEF_E  is in the numerator (top).
 rr  is in the denominator (bottom) of the big fraction on the left side of the equation.

What is the mathematical relationship between  FEF_E  and  rr  in the equation?

a)

 FEF_E  and  rr  are directly proportional to each other.

b)

 F_E  and  r  are inversely proportional to each other.

48.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

 F_E  and  r  are inversely proportional to each other.

This mathematical relationship means that as  FEF_E   increases (goes up)...

a)

 rr  also increases (goes up).

b)

 r r\  decreases (goes down).

49.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

 F_E  and  r  are inversely proportional to each other.

This mathematical relationship means that as  FEF_E   decreases (goes down)...

a)

 rr  also decreases (goes down).

b)

 r r\  increases (goes up).

50.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

 F_E  and  r  are inversely proportional to each other.

This mathematical relationship means that as  rr decreases (goes down)...

a)

 FEF_E  also decreases (goes down).

b)

 FEF_E increases (goes up).

51.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

 F_E  and  r  are inversely proportional to each other.

This mathematical relationship means that as  rr increases (goes up)...

a)

 FEF_E  also increases (goes up).

b)

 FEF_E  decreases (goes down).

52.

If a number increases by a factor of 5, what does that mean?

a)

The number gets multiplied by 5.

b)

The number gets divided by 5.

53.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

 F_E  and  r  are inversely proportional to each other.

This means that as one value increases, the other one decreases.

Let's pretend that the distance ( rr ) increases by a factor of 5.

Let's also pretend that  kk  ,  q1q_1  , and q2q_2  all stay the same (the variables in the numerator of the fraction). Since the numerator (top) of the big fraction stays the same, you can replace the numerator with the number 1 for simple demonstration purposes.

What would the result look like?

a)

 FE = 152F_{E\ }=\ \frac{1}{5^2}  

b)

 FE = 521F_E\ =\ \frac{5^2}{1}  

54.

Simplify this equation:

 FE = 152F_{E\ }=\ \frac{1}{5^2}  

a)

 FE = 125F_{E\ }=\ \frac{1}{25}  

b)

 FE = 110F_E\ =\ \frac{1}{10}  

c)

 FE = 17F_{E\ }=\ \frac{1}{7}  

55.

The equation for Coulomb's Law is:  FE = k ×q1×q2r2F_{E\ }=\ \frac{k\ \times q_1\times q_2}{r^2}  

 F_E  and  r  are inversely proportional to each other.

This means that as one value increases, the other one decreases.

Let's pretend that the distance ( rr ) increases by a factor of 5.

Let's also pretend that  kk  ,  q1q_1  , and q2q_2  all stay the same (the variables in the numerator of the fraction). Since the numerator (top) of the big fraction stays the same, you can replace the numerator with the number 1 for simple demonstration purposes.

This mathematical relationship is the result:

 FE = 125F_{E\ }=\ \frac{1}{25}  

Now, let's put it all together:
When the distance ( rr  ) increases by a factor of 5, what happens to the electrostatic force ( FEF_E  )?

a)

The electrostatic force  FEF_E  decreases and becomes 25 times weaker.

b)

The electrostatic force  F_E  increases and becomes 25 times stronger.