WorksheetsDifferential Equation
Total questions: 20
Worksheet time: 14mins
dy/dx = 4x/y. Suppose y(0)=1
The particular solution is
B
C
D
E
The following Differential Equation is
dxdy=xy
Separable.
Non Separable
Is this a Linear Differential equation
Yes
No
Maybe
red
Solve the following differential equations:
dxdy=ex
1=ex+C
y=2ex+C
y=ex+C
0=ex+C
Which functions below will have the same slope field? (choose all that apply)
y = x2 - 3
y = x2 + 4
y = 2x - 5
y = 2x2
In drawing the slope field for the differential equation , I would place short slope lines of _________ at the points (0,1), (1,-1), and (2,-2)
dxdy=2x−3y
Select all that apply
-3
-1
2
5
10
y is proportional to the product of z and the square root of x
y=zx2
y=kzx2
y=kzx
y=zkx
The degree of a differential equation is define by a
Positive real number
Positive rational number
Positive integer
All the above
Solution of a linear differential equation of first order can be obtain by
multiplying on both the sides by its integrating factor.
adding on both the sides by integrating factor.
subtracting integrating factor from both sides
None of the above
The complete solution of Linear Differential equations involves
complete function + particular integral
complementary function + particular integral
complementary function + definite integral
complete function + indefinite integral
The particular integral of the equation (D−1)y=e3x is
2e3x
2e−3x
4e3x
2ex
The C.F. of the equation (D2−9)y=e−3x+1+e3x is
c1e−3x+c2e−x
c1e3x+c2e3x
c1e3x+c2e−x
c1e3x+c2e−3x
Choose the right description for the given differential equation
Ordinary, 2nd order, degree 2, non linear
Partial, 1st order, degree 2, linear.
Ordinary, 1st order, degree 2, linear
Partial, 2nd order, degree 1, non linear
Number of arbitrary constant in the general solution of a differential equation of degree 3 and order 4 is
3
4
0
43
dy2d2x+6dydx−5y=0
The general solution to the DE is,
y=Aex+Be5x
y=Ae−x+Be−5x
y=Ae(−3+14)x+Be(−3−14)x
y=Acos(−3+14)x+Bsin(−3−14)x
Find a solution for y if dy/dx = 2x√y and y = 4 when x = 3.
2√y = x2 + C
y = (x2 + 25)2/4
y = x4/4
y = ¼(x2 - 5)2
Which of the following equations solves dy/dt = ky?
y = y0ekt
y = mx + b
y = a(x - h)2 + k
y = Asin[B(x - C)] + D
2. Solve the differential equation
𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition
𝑦(2) = 0.
y=ln∣15t∣
y=16t3
y = 2t3−16
y=2t3−16
