Worksheetspendulum
Total questions: 23
Worksheet time: 12mins
A thin uniform rod AB of length L and mass M is pivoted from a point
L/4 from vertical position and released to form a pendulum, find the Time Period of its
Oscillations?
π root(5L/6g)
2π root( 6L/7g)
2π root(7L/12g)
3π root(8L/13g)
A simple pendulum has time period T = 2 s in air. If the whole arrangement is placed in a nonviscous liquid whose density is ½ times the density of the bob. The time period in the liquid will be,
(2/√2) s
4 s
2√2 s
4√2 s
A simple pendulum suspended form the ceiling of a lift has time period T when the lift is at rest. When the lift falls freely, the time period is
infinite
T/g
zero
g/T
What is the length of a simple pendulum which ticks seconds?
0.5m
1m
8m
2m
For small swings the period of swing is approximately the same for different size swings: that is, the period is independent of amplitude. This property, called
isochronism
simple harmonic motion
oscillation
seismic activity
The two main methods of controlling a double inverted pendulum are
moving the base, as with the inverted pendulum,
by applying a torque at the pivot point between the two pendulums.
both a and b
A pair of trapeze performers at the circus is swinging from ropes attached to a large elevated platform. Suppose that the performers can be treated as a simple pendulum with a length of 16 m. Determine the period for one complete back and forth cycle.
2s
4s
6s
8s
If a pendulum-driven clock gains 5.00 s/day, what fractional change in pendulum length must be made for it to keep perfect time?
0.116%
0.0116%
1.16%
11.6%
An engineer builds two simple pendula. Both are suspended from small wires secured to the ceiling of a room. Each pendulum hovers 2 cm above the floor. Pendulum 1 has a bob with a mass of 10 kg. Pendulum 2 has a bob with a mass of 100 kg. Describe how the motion of the pendula will differ if the bobs are both displaced by 12º.
Amplitude changes by 1 cm.
Time period will change by 0.2 s.
Theta change by 0.2 rad.
The movement of the pendula will not differ at all
Natural frequency of simple pendulum depends upon
its mass
its length
square of its length
square root of its length
For simple pendulum of length ‘L’ comparable to the radius of the earth ‘R’, then the time period T =
2π √[L/(g + a)]
2π × √[L/(g^2 + a^2)^1/2]
2π [1/(g/L + g/R)]
2π × √(R/g)
The period of oscillation of a simple pendulum is T= 2π × √(L/g). Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1s resolution. The accuracy in the determination of g is :
1%
3%
2%
5%
In order to double the period of a simple pendulum, the length of the string should be
halved
doubled
quadrupled
none
You are on planet YZ and an astronaut observes that a 1.0 m long pendulum has a period of 1.50 s on the planet. What is the free-fall acceleration on YZ(in m/s^2)?
1.003
26.4
17.6
0.23
Any swinging rigid body free to rotate about a fixed horizontal axis is called a
compound pendulum
physical pendulum
Foucault pendulum
both a and b
when you see a horizontal circular motion horizontally it will look like a SHM and when you look it from the top it will look like a circular motion
true
false
If a pendulum is taken to a high altitude
it will gain time
it will lose time
time remains constant
none
What is the time period of a seconds pendulum at the surface of the moon?
2.449 seconds
2 root 6 seconds
2.45 s
2 seconds
A seconds pendulum is kept in a satellite at a distance 3R from the Earth’s surface. What is its time period
1 s
2 s
3 s
4 s
Does a simple pendulum work in a freely falling satellite?
yes
no
The period of swing of a simple gravity pendulum depends on its length and the local strength of gravity
True
False
In this figure, T is equal to
mg secθ
mg cosθ
mg cotθ
mg cosec θ
The image is false. a and v can never be perpendicular.
True, acceleration and velocity are perpendicular.
