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Unit 3 Review - General Triangles

Total questions: 27

Worksheet time: 41mins

Name
Class
Date
1.

State the number of possible triangles that can be formed using the given measurements.
 B=139°, a=12 cm, b=35 cmB=139\degree,\ a=12\ cm,\ b=35\ cm  

a)

Two Triangles

b)

One Triangle

c)

None

2.

State the number of possible triangles that can be formed using the given measurements.
 B=147°, a=25 km, b=15 kmB=147\degree,\ a=25\ km,\ b=15\ km  

a)

Two Triangles

b)

One Triangle

c)

None

3.

State the number of possible triangles that can be formed using the given measurements.
 A=36°, c=30 km, a=26 kmA=36\degree,\ c=30\ km,\ a=26\ km  

a)

Two Triangles

b)

One Triangle

c)

None

4.

What is the measure of angle A to the nearest degree?

a)

58°58\degree and 122°122\degree

b)

 78°78\degree  and  12°12\degree 

c)

78°78\degree and 102°102\degree

d)

 78°78\degree 

5.

Find the indicated angle to the nearest degree.

a)

49°49\degree

b)

29°29\degree

c)

49°49\degree and 131°131\degree

d)

29°29\degree and 151°151\degree

6.

Solve the Triangle(s):  a=14a=14 ,  b=6b=6 , A=27°A=27\degree  

a)

no triangle possible

b)

B = 11.219o, C = 141.781o, c = 19.078

c)

B = 38.219o, C = 114.781o, c = 27.998

d)

B = 11.219o, C = 141.781o, c = 19.078

OR

B = 38.219o, C = 114.781o, c = 27.998

7.

Solve the Triangle(s): A = 26o, a = 5, b = 9

a)

no triangle possible

b)

B = 14o, C = 21o, c = 8.7

c)

B = 52o, C = 102o, c = 11.2

d)

B = 52o , C = 102o, c = 11.2

OR

B = 128o, C = 26o, c = 5.0

8.

Solve the triangle
 C=103°, b=16cm, c=12cmC=103\degree,\ b=16cm,\ c=12cm  

a)

 A=67°, B=73°, a=5.7cmA=67\degree,\ B=73\degree,\ a=5.7cm  or  A=33°, B=107°, a=3.5cmA=33\degree,\ B=107\degree,\ a=3.5cm  

b)

 A=65.4°, B=74.6°, a=5.7cmA=65.4\degree,\ B=74.6\degree,\ a=5.7cm  or  A=34.6°, B=105.4°, a=3.5cmA=34.6\degree,\ B=105.4\degree,\ a=3.5cm  

c)

Not a triangle

d)

 A=65.4°, B=74.6°, a=7cmA=65.4\degree,\ B=74.6\degree,\ a=7cm  or  A=34.6°, B=105.4°, a=5cmA=34.6\degree,\ B=105.4\degree,\ a=5cm  

9.

Solve the triangle
 A=141°, c=11m, a=17mA=141\degree,\ c=11m,\ a=17m  

a)

 C=24°, B=15°, b=8mC=24\degree,\ B=15\degree,\ b=8m 

b)

 C=24°, B=15°, b=7mC=24\degree,\ B=15\degree,\ b=7m 

c)

Not a triangle

d)

 C=30°, B=9°, b=7mC=30\degree,\ B=9\degree,\ b=7m  

10.

Solve the triangle
 B=31°, a=30cm, b=25cmB=31\degree,\ a=30cm,\ b=25cm  

a)

 A=110.8°, C=38.2°, c=45.4cmA=110.8\degree,\ C=38.2\degree,\ c=45.4cm  or  A=7.2°, C=141.8°, c=6.1cmA=7.2\degree,\ C=141.8\degree,\ c=6.1cm  

b)

 C=110.8°, A=38.2°, c=47cmC=110.8\degree,\ A=38.2\degree,\ c=47cm  or  C=7.2°, A=141.8°, c=4cmC=7.2\degree,\ A=141.8\degree,\ c=4cm  

c)

Not a triangle

d)

 C=110.8°, A=38.2°, c=45.4cmC=110.8\degree,\ A=38.2\degree,\ c=45.4cm  or  C=7.2°, A=141.8°, c=6.1cmC=7.2\degree,\ A=141.8\degree,\ c=6.1cm  

11.

Find the obtuse solution of the triangle with  A=15°, a=5, b=10A=15\degree,\ a=5,\ b=10  

a)

 C=148.8°, B=16.2°, c=5.4C=148.8\degree,\ B=16.2\degree,\ c=5.4  

b)

 B=148.8°, C=16.2°, c=13.9B=148.8\degree,\ C=16.2\degree,\ c=13.9  

c)

 B=31.2°, C=133.8°, c=5.4B=31.2\degree,\ C=133.8\degree,\ c=5.4  

d)

 B=148.8°, C=16.2°, c=5.4B=148.8\degree,\ C=16.2\degree,\ c=5.4  

12.

Which scenario is the Ambiguous case concerned with?

a)

SSS

b)

SAS

c)

SSA

d)

AAS

13.

Given the triangle, find the area. Calculate to the nearest thousandth.

(a)  

14.

Given the triangle, find the area. Calculate to the nearest thousandth.

(a)  

15.

Find the area of triangle ABC.
A =  98°98\degree  , b = 13mm, c = 8mm

a)

112.4 mm2mm^2  

b)

68.9 mm2mm^2  

c)

51.5 mm2mm^2  

d)

98.2 mm2mm^2  

16.

Find the area of  ΔABC\Delta ABC  
if a = 9cm, b = 11cm, c = 16cm

a)

52.1 sq cm

b)

89.5 sq cm

c)

47.6 sq cm

d)

15.2 sq cm

17.

Find the area of  ΔABC\Delta ABC  if
a = 29in, b = 25in, c = 27 in

a)

312.2 sq in 

b)

110.6 sq in

c)

19.5 sq in

d)

786.9 sq in

18.

Find the area of triangle ABC
A =  67°67\degree  , b = 11yd, c = 24 yd

a)

209.1 yd2yd^2  

b)

58.2 yd2yd^2  

c)

112.8 yd2yd^2  

d)

121.5 yd2yd^2  

19.

Based on the given information determine the most efficient way for solving for the triangle's missing parts.

B= 70°, b=85, c=88

a)

Law of Sines

1 Triangle

b)

Ambiguous Case 0, 1, or 2 Triangles

c)

Law of Cosines

1 Triangle

20.

Based on the given information determine the most efficient way for solving for the triangle's missing parts.

A= 37°, a=8, b=14

a)

Law of Sines

1 Triangle

b)

Ambiguous Case

0, 1 or 2 Triangles

c)

Law of Cosines

1 Triangle

21.

Based on the given information determine the most efficient way for solving for the triangle's missing parts.

a = 8, c = 12, B = 57°

a)

Law of Sines

1 Triangle

b)

Ambiguos Case

0, 1, or 2 Triangles

c)

Law of Cosines

1 Triangle

22.

Based on the given information determine the most efficient way for solving for the triangle's missing parts.

V = 45°, v = 83, A = 79°

a)

Law of Sines

1 Triangle

b)

Ambiguous Case

0, 1, or 2 Triangles

c)

Law of Cosines

1 Triangle

23.
Based on the given information determine the number of unique triangles that may exist.
a = 255, b = 203, c = 172
a)
Law of Sines
1 Triangle
b)
Ambiguous Case
0, 1 or 2 Triangles
c)
Law of Cosines
1 Triangle
24.

Parker must find the distance from Point A to Point B on opposite sides of a lake. He locates Point C that is 860 feet from point A and 175 feet from Point B. He measures the angle at Point C to be 78 degrees. Find the distance from point A to point B.

a)

707643.5811

b)

841.2155

c)

707644.58

d)

841.2158

25.

In triangle ABC, a = 5, b = 6, c = 7. Which law would you need to use FIRST to solve the triangle?

a)

Law of Sines

b)

Law of Cosines

c)

Both trig laws

d)

None of these

26.

Find the length of PR by using Cosine Rule.

a)

PR2=9.2+8.5(9.2)(8.5)cos 89°PR^2=9.2+8.5-\left(9.2\right)\left(8.5\right)\cos\ 89\degree

b)

PR2=9.22+8.52(9.2)2(8.5)2cos 89°PR^2=9.2^2+8.5^2-\left(9.2\right)^2\left(8.5\right)^2\cos\ 89\degree

c)

PR2=9.22+8.522(9.2)(8.5)cos 89°PR^2=9.2^2+8.5^2-2\left(9.2\right)\left(8.5\right)\cos\ 89\degree

d)

PR2=9.22+8.52+2(9.2)(8.5)cos 89°PR^2=9.2^2+8.5^2+2\left(9.2\right)\left(8.5\right)\cos\ 89\degree

27.

What is the correct formula to find the area of ABC.

a)

12(15+12)sin 68°\frac{1}{2}\left(15+12\right)\sin\ 68\degree

b)

12(15+12)cos 68°\frac{1}{2}\left(15+12\right)\cos\ 68\degree

c)

12(15)(12)sin 68°\frac{1}{2}\left(15\right)\left(12\right)\sin\ 68\degree

d)

12(15)(12)cos 68°\frac{1}{2}\left(15\right)\left(12\right)\cos\ 68\degree