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إذا كانت h(x) = f(g(x)) فإن h'(x) =
f'(x) .g'(x)
f(g(x) ) .g'(x)
f'(g(x)) .g'(x)
f'(g(x)) +g'(x)
إذا كانت g(1) =3 , g'(1) = -2 ,f(3) = -5 , f'(3) =1
أوجد قيمة h'(1) ??
حيث h(x) = f(g(x))
-10
10
-2
2
هي f مشتقة الدالة
f′(1x). (−1x2)f'\left(\frac{1}{x}\right).\ \left(\frac{-1}{x^2}\right)f′(x1). (x2−1)
−1x2-\frac{1}{x^2}−x21
f′(1x)x\frac{f'\left(\frac{1}{x}\right)}{x}xf′(x1)
f′(1x).xf'\left(\frac{1}{x}\right).xf′(x1).x
1+f′(x2)1+f'\left(x^2\right)1+f′(x2)
2.f′(x2)2.f'\left(x^2\right)2.f′(x2)
2x.f′(2x)2x.f'\left(2x\right)2x.f′(2x)
2x.f′(x2)2x.f'\left(x^2\right)2x.f′(x2)
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