$\lim_{x\rightarrow0}\ \sqrt{4x^2-6}\ -\sqrt{4x^2-8x}\ =$  

 $\lim x\rightarrow\infty\ \sqrt{16x^2-8x\ +7\ }-\left(4x+2\right)=.\ .\ .\$  

 $Tentukan\ turunan\ dari\ y\left(x\right)=\ 2\ \sin\ 2x^2\ +\tan\ 5x$  

 $tentukan\ turunan\ dari\ f\left(x\right)\ 2\sin^3\left(4x^2+2\right)$  

 $Tentukan\ turunan\ dari\ f\left(x\right)=\ x^2\cos\ 2x$