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WorksheetsHeat Conduction:TransientHeatTransfer_ with_Heat Generation
Total questions: 10
Worksheet time: 24mins
maximum temperature will be reached at x=-L/2
maximum temperature will be reached at x= -L/4
maximum temperature will be reached at x=0
maximum temperature will be reached at x=-L/2
maximum temperature =180 degree centigrade
maximum temperature =120 degree centigrade
maximum temperature =90 degree centigrade
maximum temperature =150 degree centigrade
temperature at x=+L/2 is 150
temperature at x=+L/2 is 120
temperature at x=+L/2 is 135
temperature at x=+L/2 is 90
q''' is the volumetric heat generation rate in a cylindrical tube of inner & outer radius are r1 & r2, thermal conduction resistance of the tube in radial direction is
{1/(2*pi*k*L)}/{ln(r1/r2)}
{1/(2*pi*k*L)}/{ln(r2/r1)}
{1/(2*pi)}/{ln(r2/r1)}
Can't be defined
For Biot number calculation
Characteristic length of the plate =2L
Characteristic length of the plate =L
Characteristic length of the plate =L/2
If Biot number of a system is more than 1
temperature variation inside the solid is significant
lumped capacitance assumption can't be used
temperature variation inside the solid is insignificant
lumped capacitance assumption can be used
Biot number of the system is (assume metal is a sphere)
0.02
33.33
average of 0.02 & 33.33
insufficient information
Unit of Fourier number is
no unit
unit of time
Assuming Lumped capacitance method what will be the temperature of a 300 degree hot ball in a 50 degree C atmoshphere after a time such that Fo*Bi=ln25
60 degree C
90 degree C
120 degree C
150 degree C
Heisler chart is used to find
time in transient heat transfer problem
temperature at any radial position in a sphere after some time in transient heat transfer problem
when Biot number is more than 0.1
heat transfer in a given duration
