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WorksheetsSOM Test
Total questions: 102
Worksheet time: 51mins
Name
Class
Date
1.
The Pushing force is known as ______
a)
Compression
b)
Tensile
c)
Shear
d)
Buckling
2.
<br />The Pulling force is known as ______<br /><br /><br /><br /><br /><br /><br /><br />
a)
Compression
b)
Tensile
c)
Shear
d)
Buckling
3.
In any sheet metal operation, the material is cut by applying ___________load
a)
Compression
b)
Tensile
c)
Shear
d)
Buckling
4.
The property by which a material resists elastic deflection is called ______________
a)
Stiffness
b)
Yield limit
c)
Elastic limit
d)
Toughness
5.
The property of any material to resist penetration, absorbs or a cut is known as ___________
a)
Toughness
b)
Hardnesss
c)
Plasticity
d)
Elasticity
6.
The property of a material to recover its original shape and size when the applied force is removed ________
a)
Plasticity
b)
Elasticity
c)
Brittle
d)
Ductile
7.
The property of a material to which does not recover its original position on removal of external load is ___________
a)
Plasticity
b)
Malleability
c)
Elasticity
d)
Toughness
8.
Load / Area is equal to ________
a)
Elongation
b)
Strain
c)
Stress
d)
Torque
9.
If Load = 10KN, Area = 100mm², Find the value of stress.
a)
1 N/mm²
b)
1000 N/m²
c)
100 N/mm²
d)
10 N/m²
10.
If Stress = 120 N/mm² , Area =12 mm² Find the value of Load.
a)
100N
b)
0.1 N
c)
10N
d)
1440 N
11.
If Load = 1 KN, Area = 100 mm², Find the value of stress
a)
0.1 N/mm²
b)
100 N/mm²
c)
10 N/mm²
d)
1000 N/mm²
12.
1 x 10³ N = _____
a)
1 MN
b)
1 KN
c)
1 GN
d)
1 GN
13.
The formula for Load P = ______________.
a)
&lAE/l
b)
PI/AE
c)
AE/PL
d)
PE/AL
14.
The unit of Load is __________
a)
N/mm
b)
N mm
c)
N
d)
N /mm³
15.
The ability of a material to absorb energy and plastically deform without fracturing is _____________
a)
Toughness
b)
Hardnesss
c)
Plasticity
d)
Elasticity
16.
The formula for Strain is ______
a)
stress X E
b)
Load xE/Area
c)
Area/Load X E
d)
stress / E
17.
The formula for Load is _________
a)
Area/Load
b)
Area/Stress
c)
Stress X Area
d)
Stress/Strain
18.
If Original length of a rod is 250 mm, change in length is 0.02 mm , Find the value of strain _________
a)
0.8
b)
0.008
c)
8.0E-4
d)
8.0E-5
19.
The unit of Stress is _____
a)
N/mm
b)
N mm
c)
N/mm²
d)
N /mm³
20.
The unit of Strain is _______
a)
mm
b)
No unit
c)
mm²
d)
mm³
21.
Change in length / original length is equal to __________
a)
Stress
b)
Volumetric Strain
c)
Elastic modulus
d)
strain
22.
The formula for Young's Modulus E = _________
a)
load/Area X Strain
b)
Load x Strain/Area
c)
Area/load x Strain
d)
Strain/Area x Strain
23.
Convert 1 GPa = ________N/m²
a)
1 X 10² N/m²
b)
1 X 10² N/m²
c)
1 X 10 N/m²
d)
1 X 10³ N/m²
24.
Convert 1 Pa = ________N/m²
a)
1 N/mm²
b)
1 N/m²
c)
1000 N/mm²
d)
10 N/m²
25.
Convert 1 N / mm² = __________MPa
a)
10 Mpa
b)
1000 Mpa
c)
1 Mpa
d)
100 Mpa
26.
In Hook's Law, within _________ Stress is directly proportional to strain
a)
No limit
b)
Plastic limit
c)
Elastic limit
d)
Toughness
27.
Modulus of Elasticity is also known as ____________
a)
Bulk modulus
b)
Modulus of rigidity
c)
Young's Modulus
d)
Poisson ratio
28.
Convert 1 Mpa = ____________N / mm²
a)
1 N/m²
b)
1 N/mm²
c)
1 X 10^5 N/m²
d)
1 X 10^3 N/m²
29.
The value of Modulus of elasticity for steel is _______
a)
5 x 10⁵ N/mm²
b)
20 x 10⁵ N/mm²
c)
2 x 10⁵ N/mm²
d)
10 x 10⁵ N/mm²
30.
The unit of modulus of Elasticity is _______
a)
N/mm²
b)
N/m³
c)
N/mm
d)
N/m²
31.
The formula for Elongation of a wire due to self weight if specific weight is given _______
a)
wl2/2E
b)
wl2/E
c)
wl2/PE
d)
wl2/AE
32.
Area of base of a square bar is 36 mm² load acting on it is 360 N. What is the value of stress _______
a)
10 N/mm²
b)
1N/m²
c)
1000N/mm²
d)
100N/m²
33.
The formula for Modular ratio of two materials making up the composite bar is ______________
a)
E1/E2
b)
M1/M2
c)
S1/S2
d)
e1/e2
34.
The formula for Elongation = ____________
a)
PA/LE
b)
PL/AE
c)
PE/AL
d)
AE/PL
35.
The formula for Possion's ratio is ___________
a)
lateral strain/longitudinal sttrain
b)
shear stress/shear strain
c)
longitudinal strain/lateral strain
d)
volumetric stress/volumetric strain
36.
The Unit for Possion's ratio is ___________
a)
N/mm²
b)
N/mm
c)
No unit
d)
Nmm
37.
The notation for Possion's ratio is ___________
a)
1/2m
b)
1/m
c)
m
d)
2/m
38.
The formula for longitudinal strain is _____________
a)
change in length / original length
b)
change in width / original width
c)
change in thickness / original thickness
d)
change in volume / original volume
39.
The formula for Modulus of Rigidity is___________
a)
stress / strain
b)
shear stress /shear strain
c)
Longitudinal stress / Volumetric strain
d)
volumetric stress/volumetric strain
40.
The formula for Bulk Modulus is _______________
a)
stress / strain
b)
shear stress /shear strain
c)
Longitudinal stress / Volumetric strain
d)
volumetric stress/volumetric strain
41.
The formula for lateral strain is _____________
a)
change in length / original length
b)
change in width / original width
c)
change in cross section / original cross section
d)
change in volume / original volume
42.
The formula for volumetric strain is _____________
a)
change in length / original length
b)
change in width / original width
c)
change in thickness / original thickness
d)
change in volume / original volume
43.
The value of modulus of elasticity for copper is ___________
a)
20x10^5 N/mm²
b)
2x10^5 N/mm²
c)
10x10^5 N/mm²
d)
1x10^5N/mm²
44.
The parallel portion of the tensile test specimen over which the elongation is measured is ______________
a)
Gauge length
b)
width
c)
Entire length
d)
thickness
45.
The formula for Ultimate strength is _________
a)
Minimum load/orignal area of cross section
b)
Maximumload/orignal areaof cross section
c)
Minimum load/total surfaceof cross section
d)
Maximum load/total surface of cross section
46.
The load which requires to break the material is known as _________
a)
Fracture load
b)
Shear load
c)
tensile load
d)
Ultimate load
47.
The ratio of ultimate stress to the permissible stress is called ____________
a)
Factor of safety
b)
Modulus of rigidity
c)
Yield stress
d)
Ultimate tensile stress
48.
The formula for Shear Stress is _______
a)
Shear load / Area
b)
Ultimate load / Area
c)
Area / Shear load
d)
Area / Shear force
49.
The unit of shear strain,θ is __________
a)
N
b)
N/mm2
c)
Radian
d)
Nmm
50.
E = 9 KG / (3K+G) in this equation the G is __________
a)
Young's modulus
b)
Bulk modulus
c)
Modulus of rigidity
d)
Modulus of elasticity
51.
E = 9 KG / (3K+G) in this equation the E is _________
a)
Bulk modulus
b)
Modulus of rigidity
c)
Modulus of elasticity
d)
Shear Modulus
52.
The forumula for Shear Strain is _________
a)
Shear Stress/Young's modulus
b)
Shear stress/ Rigidity modulus
c)
shear stress/bulk stress
d)
shear stress/ Modulus of Elasticity
53.
Fine blanking operation in a stamping process is an application of _______________ stress
a)
Tensile
b)
Compressive
c)
Shear
d)
Buckling
54.
If the shear load is 15 KN and area of cross section is 78.6mm². Find the shear stress ___________
a)
191 N/mm²
b)
0.191 N/mm²
c)
1.91 N/mm²
d)
19.1 N/mm²
55.
If the shear load is 15 KN and area of cross section is 78.6mm² and shear stress=191 N/mm² Find the diameter of the rod is _______
a)
100m
b)
96 N
c)
10 mm
d)
None of the above
56.
If the shear load is 15KN and diameter of the rod 10mm. Find the shearstress ________
a)
191 N/m²
b)
191 N m²
c)
191 Mpa
d)
191 N-mm²
57.
if the shear load is 15 KN and the shear stress is 190.83 N/mm². find the area __________
a)
2854 mm²
b)
78.56 N/mm²
c)
78.56 mm²
d)
258.4 m²
58.
The formula for Tempreature Stress if the expansion is prevented is ______________
a)
aTl
b)
EaT
c)
alT/2
d)
Eat/2
59.
The property which descirbes how the size of an object changes with a change in temperature _____________
a)
Elasticity
b)
Plasticity
c)
Coefficient of thermal expansion
d)
Elastic Limit
60.
The stress which is induced due to change in temperature is known as __________
a)
shear stress
b)
Normal stress
c)
Thermal stress
d)
Thermal strain
61.
The change in the length is directly propostional to _________
a)
temperature
b)
length
c)
width
d)
Thickness
62.
The temperature stress is directly propostional to ___________
a)
temperature
b)
length
c)
width
d)
Thickness
63.
The deformation of length due to _______
a)
Only increase in the temperature
b)
only decease in temperature
c)
Both a & b
d)
Does not affect with temperature
64.
Find out the correct formula for free expansion _________
a)
aTL
b)
aTG
c)
aTE
d)
at
65.
When the temperature of a body is increased, and if the body is not allowed to expand ,thee the stress induced will be due to ____________
a)
Tension
b)
Compression
c)
shear force
d)
elasticity
66.
The unit of teperature coefficient _____________
a)
Kelvin
b)
wattt
c)
°c
d)
/°c
67.
The unit of Young's Modulus is ________
a)
N/mm²
b)
N/m³
c)
N/mm
d)
N/m²
68.
Find the change in length, if a = 0.000012/°c , L = 500mm and T = 70°c
a)
0.42mm
b)
0.25mm
c)
0.2mm
d)
0.3mm
69.
Find the temperature strain if the the thermal expansion is fully prevented having temperature rise is 70° , a = 0.000012 per °c
a)
5.0E-4
b)
8.4E-4
c)
6.0E-4
d)
3.0E-4
70.
Find the tempetrature stress if the temperature rise is 90° , a = 0.000012 per°c and E=1 x 10³ N/mm²
a)
108 N/mm²
b)
10.8 N/mm²
c)
1.08 N/mm²
d)
75 N/mm²
71.
Find the change in length, if the initial temperature is 90° and final temperature is 30 , a = 0.000012 per°c and l =500 mm
a)
0.36 mm
b)
0.006 cm
c)
0.00072 mm
d)
0.036 mm
72.
Find the Temperature difference If the free expansion is 0.36 mm, a = 0.000012 per °c and L = 500 mm
a)
65 °c
b)
30 °c
c)
60 °c
d)
50 °c
73.
Find the temperature stress if the expansion is prevented for T =40° , L =500 mm, a = 0.000017 per °c and E = 2 x 10³N/mm²
a)
136 N/m²
b)
1.36 Mpa
c)
136 Gpa
d)
136 Mpa
74.
Find the temperature difference if temperature stress = 30 Mpa , L= 500 mm, a =0.000017 per °c and E = 2 x 10³N/mm²
a)
65 °c
b)
30 °c
c)
40 °c
d)
50 °c
75.
A member of a truss under compressive load is called as _________
a)
Stanchion
b)
Boom
c)
Post
d)
Strut
76.
The vertical member which is subjected to an axial load is called
a)
Strut
b)
Post
c)
Composite bar
d)
Column
77.
The load at which the column just buckle is ____________
a)
Ultimate load
b)
Crushing load
c)
Buckling Load
d)
Yield load
78.
Example for column is ____________
a)
Pendulum
b)
conecting rod
c)
pillar
d)
Beam
79.
In End condition of column which of the following is not correct ?
a)
Both the end hinged
b)
One end fixed, other end free
c)
Both the ends fixed
d)
Slides are pressed
80.
The buckling load is 6 KN, factor of safety = 4, then the safe load is ______
a)
0.33KN
b)
24KN
c)
1.5KN
d)
0.66KN
81.
The buckling load on both the ends fixed is _____ times the buckling load on both the ends hinged
a)
2
b)
1¤2
c)
1¤4
d)
4
82.
The buckling load for long column is ____ that of short column
a)
Less
b)
more
c)
equal
d)
None of these
83.
which of the following is not comes under the Assumptions made in Euler's column theory
a)
The cross-sectional of the column is uniform
b)
The column is not straight
c)
The length of the column is very large
d)
The column fails only by buckling
84.
which of the following is not comes under the Assumptions made in Euler's column theory
a)
The cross-sectional of the column is uniform
b)
The column is perfectly straight
c)
The length of the column is very large
d)
The column fails only by crushing
85.
Unit of buckling load is ____________
a)
Nm
b)
Newton
c)
Watt
d)
mm
86.
Considering the end condition of column when both ends are hinged
a)
Effective length L = l
b)
Effective length L = 2l
c)
Effective length L = Ö/
d)
Effective length L = Ö I / A
87.
Considering the end condition of column when both ends are fixed
a)
Effective length L = l
b)
Effective length L = 2l
c)
Effective length L = l/2
d)
Effective length L = l/Ö2
88.
Considering the end condition of column when one end fixed and end other end free.
a)
Effective length L = l
b)
Effective length L = 2l
c)
Effective length L = l/2
d)
Effective length L = l/Ö2
89.
Considering the end condition of column, when one end fixed and end other end hinged
a)
Effective length L = l
b)
Effective length L = 2l
c)
Effective length L = l/2
d)
Effective length L = l/Ö2
90.
The formula for Slenderness ratio is ___________
a)
Effective length/ least radius of gyration
b)
Poisson's ratio
c)
Modular Ratio
d)
None of these
91.
The formula for Permissible stress =
a)
Ultimate stress x factor of safety
b)
Ultimate stress / Factor of safety
c)
Factor of safety / ultimate stress
d)
shear stress / Factor of safety
92.
The formula for Efective length =
a)
Least radius of grydation / slenderness ratio
b)
slenderness ratio / Least radius of gyration
c)
slenderness ratio x least radius of gyration
d)
Poisson ratio x least radius of gyration
93.
A strut in which ends are hinged, the length of the strut is 1800mm. Find the effective length
a)
900 mm
b)
1350 mm
c)
675.8 mm
d)
1800 mm
94.
A strut in which both ends are hingrd the length of the strut is 525mm find the effective length
a)
600 mm
b)
900 mm
c)
525 mm
d)
1150 mm
95.
The buckling load P =
a)
p² EI/1²
b)
p² E/I1²
c)
p² I/E1²
d)
p² E/1²
96.
A strut in which one end is fixed and other end is free the length of two of strut is 1200mm find the effective length
a)
1200mm
b)
2400mm
c)
600mm
d)
1800mm
97.
P=p²EI/L² where E is the youngs modulus, L is the effective length I is the moment of inertia. Then P=?
a)
Crushing load
b)
Shear load
c)
Crippling load
d)
Ultimate load
98.
Buckling load P = p²EI /L² where E is young's modulus,I is the moment of inertia L=?
a)
Length
b)
Effective length
c)
Total length
d)
None of these
99.
Considering the end condition of column when both ends are hinged then the buckling force is
a)
p²EI/1²
b)
p²EI/41²
c)
4p²EI/1²
d)
2p²EI/1²
100.
Considering the end condition of column when one end fixed and other end free then the buckling force is
a)
p²EI/1²
b)
p²EI/41²
c)
4p²EI/1²
d)
2p²EI/1²
101.
Considering the end condition of column when both ends are fixed then the buckling force is
a)
p²EI/1²
b)
p²EI/41²
c)
4p²EI/1²
d)
2p²EI/1²
102.
Considering the end condition of column when one end fixed and other end hinged then the buckling force is
a)
p²EI/1²
b)
p²EI/41²
c)
4p²EI/1²
d)
2p²EI/1²
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