Font size
WorksheetsAssessment SM025 Week 2 (Miss jade)
Total questions: 21
Worksheet time: 37mins
If y = axn , then ∫y dx =
n+1axn+1
n−1axn−1+ c
naxn+1+ c
n+1axn+1+ c
Integrate x with respect to x
x21+c
21x−21+ c
32x23+ c
23x23+ c
Integrate ∫(2x+1)10 dx with respect to x.
22(2x+1)11+c
221(2x+1)11+c
11(2x+1)10+c
111(2x+1)10+c
∫ x1+ x21 dx
x−1 + x−2+ c
x0 − x−1+ c
lnx+ x−1+ c
lnx− x−1+ c
Integrate sin(2x) with respect to x
cos(2x) + c
−2cos(2x) + c
−cos(2x) + c
−21cos(2x) + c
∫sec2 5x dx =
tan x + c
51tan x + c
51tan 5x + c
51tan2 5x + c
Find the integral with respect to x of ∫ (e3x)2 dx .
6e6x + c
9e9x + c
6e6x + c
(e3x)2 + c
Find indefinite integral for ∫e5x1 dx
51e5x + c
−5e4x + c
−5e−5x+ c
−4e−4x+ c
∫ 6 x (x2 +1 )2 dx
( x2 + 1)3 + C
3 ( x2 + 1)3 + C
( x2 + 1)1 + C
6 ( x2 + 1)3 + C
∫ 2x cos(x2) dx
sin(x2) + C
2 sin ( 2x ) + C
(1/2) sin(x2) + C
4 cos(2x ) + C
∫ x (x2 + 7 )(1/3) dx
(3/4) ( x2+ 7 )(4/3) + C
(3/8) ( x2+ 7 )(4/3) + C
( x2+ 7 )(4/3) + C
(3/2) ( x2+ 7 )(4/3) + C
∫ g ' ( x ) f (u) dx, u = g ( x )
∫ f ( u ) du
g ( x ) + C
( 1/ g ( x ) ) g ( x)4 + C
cannot be determined
What is the choice of u for ∫ ex(1+ex)(1/2) dx?
ex
1+ex
(1+ex)(1/2)
(ex)(1/2)
What is the Integration by Parts Formula?
Evaluate the indefinite integral using integration by parts. u and v ' are provided.
∫tsint dt ; u=t, v ′=sint
tcos−1t−(1−t2)21+C
−tcost+sint+C
tsin−1t+(1−t2)21+C
tsint+cost+C
A
B
C
D
What would you choose for your u here if you used integration by parts?
t
3t
e2t
et
don't use IBP, let u = 2t
Determine ∫x sin2x dx
2−x sin2x+4cos2x+c
4−x cos2x+2sin2x+c
2−x cos2x+4sin2x+c
−x sin2x+cos2x+c
Evaluate the indefinite integral using integration by parts.
∫t⋅2t dt ;
2t2ln2t2−t2+C
ln2t⋅2t−(ln2)22t+C
3t3lnt−9t3+C
32t23ln2t−94t23+C
What is the solution of following :(please leave your answer in small letter)
(a)
