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CHEMSCORE Chapter 1 - 3

Total questions: 10

Worksheet time: 11mins

Name
Class
Date
1.

The iodide ion reacts with hypochlorite ion in the following way:

OCl- + I- ⟶ OI- + Cl-.

This rapid reaction gives the rate data shown. What is the rate law?

a)

rate = [OCl-]2[I-]

b)

rate = [OCl-][I-]2

c)

rate = [OCl-][I-]

d)

rate = [OCl-]

2.

Which of the following plots will show a linear relationship for a second order reaction?

a)

[A] vs time

b)

1/[A] vs time

c)

ln[A] vs time

d)

[A]2 vs time

3.

A reaction is found to be second order with respect to carbon monoxide. If the concentration of carbon monoxide is doubled, the rate of reaction __________.

a)

doubles

b)

remains unchanged

c)

increases by a factor of 4

d)

is reduced by a factor of 2

4.

The heat released when 1 mole of ionic compound is formed from its gaseous ions. This is the enthalpy of.....

a)

Lattice energy

b)

Formation

c)

Lattice energy dissociation

d)

Ionisation

5.

Identify the enthalpy change represented by letter g.

a)

Enthalpy of formation

b)

Enthalpy lattice of formation

c)

Electron affinity of bromine

d)

Enthalpy of atomisation of zinc

6.

Factors affecting the value of lattice energy

a)

the size of the ions only

b)

the charges of the ions only

c)

BOTH the size of the ions AND the charges of the ions

7.
If the specific heat of water is 4,186 J/kg∙°C, how much heat is required to increase the temperature of 1.2 kg of water from 23 °C to 39 °C? 
a)
-80,371.2
b)
44,938.6
c)
80,371.2
d)

80.371

8.

A VCE chemistry student sets up a galvanic cell using two standard half-cells with half reactions. Half-cell 1: Cr3+(aq)+e-→Cr2+(aq) Half-cell 2: Cr(s)→Cr2+(aq)+2e- Suitable materials for the electrodes of the two half-cells are

a)
Half-cell 1: Platinum; Half-cell 2: Platinum
b)
Half-cell 1: Platinum; Half-cell 2: Chromium
c)
Half-cell 1: Chromium; Half-cell 2: Chromium
d)
Half-cell 1: Chromium; Half-cell 2: Platinum
9.

A VCE chemistry student sets up a galvanic cell using two standard half-cells with half reactions.

Half-cell 1: Cr3+(aq)+e-→Cr2+(aq)

Half-cell 2: Cr(s)→Cr2+(aq)+2e-

Using this information, we can determine that;

a)

Half-cell 1 is the anode, where oxidation occurs

b)

Half-cell 1 is the cathode, where reduction occurs

c)

No spontatneous reaction will occur, since only chromium is involved

d)

Cr3+ is the reductant, since it undergoes reduction

10.

Calculate the E cell of following half cell.

Half-cell 1: Cr(aq)+ 3e-→Cr3+(aq)

Half-cell 2: Cu2+(s)→Cu+(aq)+e-

Given the E0 cell = 0.89 V; [Cr3+] = 0.5 M; [Cu+]= 0.1M; [Cu2+] = 0.5 M

a)

+0.94 V

b)

+1.41 V

c)

+0.35V