WorksheetsPES spectroscopy
Total questions: 96
Worksheet time: 1hrs 10mins
How many peaks would be expected for a PES spectum for Calcium?
2
3
4
5
Which of these elements would have the same number of PES peaks as Fluorine?
Neon
Beryllium
Sodium
Chlorine
Which of these elements would have the same number of PES peaks as Fluorine?
Neon
Beryllium
Sodium
Chlorine
The PES spectrum below is for the element _______________.
O
Ne
N
F
Examine the spectrum below. Where would you expect the 2p peak for F be if it were on the same spectrum?
To the left of the peak at 3.04
To the right of the peak at 3.04
To the left of the peak at 1.31
To the right of the peak at 1.31
Which peak (or peaks) correspond to the valence electrons?
The peak at 1
The peaks at 1 and 2.05
The peak at 239
The peaks at 239 and 22.7
Identify the Electron Configuration for Aluminum (Al)
1s2 2s2 2p6 3s2 3p1
1s2 2s2 2p6 3s2 3p3
1s2 2s2 2p6 3s2 4p1
P, Cs, Co, Sr
Which of the following elements has the smallest atomic radius?
Sulfur
Chlorine
Aluminum
Sodium
Which atom has the largest atomic radius?
potassium
rubidium
francium
cesium
Which has the SMALLER radius?
Mg 2+
S 2-
Which atom has the LOWER ionization energy?
Al
Cl
Vibrating diatomic molecule obeys
Hookes law
Law of motion
Law of conservation of energy
none
Q Branch
DJ=0
DJ = ±1
DJ=-1
DJ =1
P Branch
DJ=0
DJ=1
DJ=-1
DJ=±1
R Branch
DJ = ±1
DJ = 0
DJ = +1
DJ = -1
BAND CENTER OCCURS AT
⍵
⍵eXe
⍵osc
⍵0
Zero point energy of S.H.O is
⍵osc
⍵e
1/2 ⍵osc
ALL
Hertz can be converted cm-1 dividing by
hc
h
h/n
h/⍵
Selection rule for SHO is
Dv =0
Dv =0,±1
Dv =±1
none
Selection rule for anharmonic oscillator
Dv =±1
Dv =0,±1
Dv =±1,±2,±3
none
MOARSE CURVE IS THE PLOT OF
ENERGY VERSUS BONDLENGTH
ENERGY VERSUS BOND DISSOCIATION ENERGY
ENERGY VERSUS INTERNUCLEAR DISTANCE
DISSOCIATION ENERGY VERSUS INTERNUCLEAR DISTANCE
First overtone occurs at
⍵e(1-4Xe)
⍵e(1-3Xe)
2⍵e(1-3Xe)
⍵e(1-Xe)
Xe is called
Rotational constant
Anharmonicity constant
Oscillation frequency
Wavenumber
HOT BANDS OCCURS AT
⍵e(1-4Xe)
⍵e(1-2Xe)
⍵e(1-3Xe)
2⍵e(1-2Xe)
DJ = -2
Q BRANCH
S BRANCH
P BRANCH
O BRANCH
HOT BANDS OCCUR AT
HIGH TEMPERATURE
LOW TEMPERATURE
HIGH INTENSITY
LOW INTENSITY
IN ALL BRANCHES OF SPECTROSCOPY THE UPPER LEVEL IS REPRESENTED BY
SINGLE PRIME
DOUBLE PRIME
ZERO
NONE
In S.H.O Oscillator, the energy levels are
EQUALLY SPACED
INCREASING SPACING
DECREASING SPACING
NONE
Fundamental vibration occurs at
⍵e(1-Xe)
⍵e(1-2Xe)
2⍵e(1-2Xe)
⍵e(1-3Xe)
In vibrational spectroscopy v is called
vibrational quantum number
rotational quantum number
oscillation quantum number
none
Condition for the molecule to be vibrational active
permanent dipole moment
change in dipolemoment
change in polarisibility of the molecule
All
Homonuclear diatomic molecules with no permanent dipole moment show
Vibrational spectroscopy
Rotational spectroscopy
Electronic spectroscopy
NMR
In vibrational analaysis of a band system the energy of the v=--- level is taken as zero
0
1
2
3
In V" progression
V' varies & v" is constant
V" varies & v' is constant
Both varies
None of these
A straight line representing a transition between electronic states will be
Inclined with x axis
Inclined with Y axis
Horizontal
Vertical
Which of the following molecules is NMR active
Helium
Carbon
Boron
Oxygen
The type of relaxation in NOE is
Spin spin
Spin Lattice
Dipole Dipole
Can't b predicted
In general Chemical shift is measured in
Ppm
Ppb
Ppt
Cm-1
The intensity ratio of the line CHO in CH3-CHO in NMR is
1:1
1:2:1
1:3:3:1
1:3:1
The frequency in ESR falls in
Gamma ray region
Microwave
RF
IR
The hyperfine structure in ESR is due to
Nuclear spin -spin coupling
Electron spin-spin coupling
Both a and b
Nuclear spin with electronic spi
The electronic spectra in the visible range span is __________
25000-72000 cm-1
25000-50000 cm-1
12500-25000 cm-1
15000-30000 cm-1
Which of the following transitions are of weak intensities and lie in the visible region?
n→π*
σ→σ*
π→π*
n→σ*
Which of the following transitions are of weak intensities and lie in the visible region?
n→π*
σ→σ*
π→π*
n→σ*
Which of the following transitions are of weak intensities and lie in the visible region?
n→π*
σ→σ*
π→π*
n→σ*
Arrange the various electronic transitions in the order of increasing energy.
n→σ* < π→π* < n→π* < σ→σ*
n→π* < π→π* < n→σ* < σ→σ*
n→σ* < n→π* < π→π* < σ→σ*
σ→σ* < π→π* < n→π* < n→σ*
Which of the following is not an auxochrome group?
–OH
–SH
–OR
–O2
Which of the following shift leads to the decreased intensity of absorption?
Hypochromic
Hyperchromic
Hypsochromic
Bathochromic
Increase in the intensity of absorp in UV-Visible spectrum is called
Hypsochromic
Bathochromic
Hyperchromic
Hypochromic
An absorption towards longer wavelength is called
Bathochromic shift
Hypsochromic shift
Hyperchromic shift
Hypochromic shift
An absorption towards shorter wavelength is called as
Bathochromic shift
Hypsochromic shift
Hyperchromic shift
Hypochromic shift
Methane molecule show ------- electronic transition
σ→σ*
π→π*
n→π*
n→σ*
In hyperchromic shift, extinction coefficient is
Small
Large
No change
None of the above
The different types of energies associated with a molecule are __________
Vibrational energy
electronic energy
Rotational energy
All of these
Molecules which are having _______ are microwave active.
Dipole moment
High pressure Detector
Principle axis
Acidity
A photon of wave number 100 cm-1 has a wavelength of
1 m
1 mm
1000 nm
100 m
The photon described in Question 3 lies within which part of the electromagnetic spectrum?
Radio wave
Visible
Infrared
Ultraviolet
The energy in joules of a photon of wavelength 355 nm is
5.596 x 1019 J
5.596 x 1028 J
Calculate the moment of inertia, I, of the molecule 1H35Cl. The masses of the two atoms are mH = 1.673 x 1027 kg and mCl = 5.807 x 1026 kg. The equilibrium bond length of the molecule is 1.275 Å.
2.644 x 1047 kg m2
2.644 x 1027 kg m2
2.644 x 1044 kg m2
2.644 x 1024 kg m2
Which of the following molecule has no rotational spectrum?
NH3
HCl
N2
H2O.
The microwave active molecules are
HCl, OCS
CO,CO2
Both a) and b)
None of the above
From the rotational microwave spectrum of 1H35Cl, we find that B = 10.59342 cm-1 . Given that the masses of 1H and 35 Cl are 1.0078250 and 34.9688527 amu, respectively, determine the bond length of the 1H35Cl molecule
1.274 x 10-10 m
1.674 x 10-10 m
1.474 x 10-10 m
1.0274 x 10-10 m
The correct order of different types of energies is __________
Eel >> Evib >> Erot
Eel >> Erot >> Evib
Evib >> Eel >> E rot
None of these
CONDITION FOR THE MOLECULE TO BE MICROWAVE ACTIVE
CHANGE IN DIPOLEMOMENT
CHANGE IN POLARSIBILITY
PERMANENT DIPOLE MOMENT
ALL
Which of the following type of electromagnetic radiation has the most energy
infrared
ultraviolet
microwaves
radiowaves
Which of the following molecules show microwave activity?
H2
CO2
SF6
CH3Cl
The rotational energy of a diatomic molecule in terms of wave number is
EJ = 8π2IChJ(J+1)
EJ = 8π2ICh2J(J+1)
EJ =8π2Ih2 J(J+2)
The wave number difference between successive rotational levels of a rigid diatomic molecule is
2B J
BJ(J+1)
2BJ(J+1)
2BJ(J-1)
The various energy level of a rotational spectrum is given by
2B,6B,12B,_ _ _
2B,4B,6B,8B,….
0,2B,6B,12B,_ _ _
0,2B,4B,6B,8B,….
The different types of energies associated with a molecule are __________
Vibrational energy
electronic energy
Rotational energy
All of these
Molecules which are having _______ are microwave active.
Dipole moment
High pressure Detector
Principle axis
Acidity
The correct order of different types of energies is __________
Eel >> Evib >> Erot
Eel >> Erot >> Evib
Evib >> Eel >> E rot
None of these
The arrangement of various type of Electromagnetic radiation in the order of their
wavelength,frequency
Energy,velocity
Speed,Rate
None
Joules can be converted to cm-1
Multiply by h
Multiply by hc
Divide by h
Divide by hc
Rotational spectrum is useful to determine the
(a)
Intensity of spectral lines depends on
energy of the energy level
population of the energy level
J value
B Value
Plot of NJ/N0against J gives
Boltzmann curve
Gaussian curve
Parabola curve
Morse curve
The molecule which is microwave active
H2
O2
HCl
co2
The wavelength range of rotational spectrum is
10-2 to 10cm
1 to 10cm
10 to 100 cm
1 to 1000cm
As J value increases, the energy of the energy level
Increases
Decreases
Remains same
Remains constant
Selection rule of rotational spectrum
,Dn=±1
DS=0
,DJ=±1
,DJ=0
The rotational spectrum consits of a series of lines at
2B
B
4B
6B
Bond length can be determined using
Moment of inertia
Energy
Angular momentum
Plancks constant
How many peaks would be expected for a PES spectum for Calcium?
2
3
4
5
Which of these elements would have the same number of PES peaks as Fluorine?
Neon
Beryllium
Sodium
Chlorine
The PES spectrum below is for the element _______________.
O
Ne
N
F
Examine the spectrum below. Where would you expect the 2p peak for F be if it were on the same spectrum?
To the left of the peak at 3.04
To the right of the peak at 3.04
To the left of the peak at 1.31
To the right of the peak at 1.31
What does the 4th peak from the left represent?
The 2s electrons
The 3d electrons
The 2p electrons
The 3s electrons
Which peak (or peaks) correspond to the valence electrons?
The peak at 1
The peaks at 1 and 2.05
The peak at 239
The peaks at 239 and 22.7
How many valence electrons does the element pictured in the PES spectrum below have?
1
2
3
4
Where would you expect the 2s peak for Sodium to fall relative to the presented spectrum of a different element below?
Just to the left of the peak at 126
Just to the right of the peak at 126
Just to the left of the peak at 9.07
Just to the right of the peak at 9.07
Which peak (or peaks) correspond to valence electrons?
The peak at 0.8
The peaks at 0.8 and 1.36
The peak at 19.3
The peaks at 19.3 and 1.36
