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WorksheetsDifferential Equations Exam
Total questions: 111
Worksheet time: 1hrs 26mins
Given the differential equation dP/Dt=5P
A) Find the general solution for P to the differential equation
B)Find the particular solution for P to the differential equation given P(0)= 418
A) P=Ce5t
B) P= 5e418t
A) P=Ce5t
B) P= 418e5t
A) P=Cet
B) P= 418et
A) P=Ce10t
B) P= 418e10t
The population of the little town of Scorpion Gulch is now 1000 people. The population is presently growing at about 5% per year.
Find the general solution.
P=.05e1000t
P=1000e5t
P=1000e.05t
p=lne1000t
Y is proportional to the difference of x and z
y= x-z
y= k(z-x)
y= k(x-z)
y= z-x
dy/dx = 2x/e2y find the general solution
y = ln (2x/2 + C)
2
y = ln(2x/2)+c
y = e2x+c
y = mx+b
2. Solve the differential equation
𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition
𝑦(2) = 0.
𝑦 = ln(15t)
𝑦 = 16t3
𝑦 = (2𝑡3 − 16)1/2
𝑦 = (2𝑡3 −16)
dy/dx= x √y
Find the general solution
√y = ln|4x| + c
√y = (x)-1 + c
2y1/2 = ln|x| + c
1/2y1/2 = ln|x| + c
y varies jointly with x and the square of z
y= kxz2
y= kx√z
y= kxz
kx2z
what would the sign of the square root after finding c be given the initial condition g(1)= -5
positive
negative
Dy/dx= tanx+15x2+ex+1/x
y= -ln|sinx| + 5x3 + ex + ln|x| + c
y= secxtanx + 5x3 + ex + ln|x| + c
y= -ln|cosx| + 5x3 + ex + ln|x| + c
y= sec2(x) + 5x3 + ex + ln|x| + c
dp/dy = (4y)-1find the general solution
p= 1/5y5/4 + c
p= 1/4ln|4y| + c
p= 1/8y2 + c
p= 1 + c
4y
y is proportional to the product of z and the square root of x
y= z(x2)
y= kz(x2)
y= kx√z
y=zkx
dy/dx = 4x/y. Suppose y(0)=1
The particular solution is
B
C
D
E
Find the particular solution for y if dy/dx = 2x√y and y = 4 when x = 3.
2√y = x2 + C
y = (x2 + 25)2/4
y = (x2/2-5/2)1/2
y = x4/4
How would you CORRECTLY separate the following differential equation?
dxdy=3y2x+1
3y⋅dy=(2x+1)dx
3ydy=(2x+1)dx
3ydy=2x+1dx
3y−1dy=(2x+1)dx
Now that we have separated, what would be the correct integration?
3y⋅dy=(2x+1)dx
3ln∣y∣=x2+x+C
23y2dy=x2+x
23y2=x2+x+C
3y2=21x2+x+C
How would you CORRECTLY separate the following differential equation?
dxdy=2y−xy
y1dy=(2−x)dx
y⋅dy=(2−x)dx
ydy−2y=xdx
y−2y+dy=x⋅dx
y1dy=(2−x)dx Now that we have separated, what would be the correct integration?
ln(y)=x−x2+C
ln∣y∣=2x−21x2+C
−21y−2=x−21x2+C
ln∣y∣=21x2−2x+C
How would you CORRECTLY separate the following differential equation?
dxdy=e(x+y)
e−ydy=exdx
−eydy=exdx
e(x+y)dy=1dx
1dy=e(x+y)dx
Now that we have separated, what would be the correct integration?
e−ydy=exdx
ey=ex+c
e−y=ex+c
−e−y=−ex+c
−e−y=ex+C
In drawing the slope field for the differential equation , I would place short slope lines of _________ at the points (0,1), (1,-1), and (2,-2)
dxdy=2x−3y
Select all that apply
-3
-1
2
5
10
Which choice below represents this slope field?
dy/dx = 2x
dy/dx = -x
dy/dx = yx
dy/dx = x2
Which equation below represents the slope field?
dy/dx = x - 2
dy/dx = 1/2x + 1
dy/dx =1/2 y - 2
dy/dx = y + 2
Which functions below will have the same slope field? (choose all that apply)
y = x2 - 3
y = x2 + 4
y = 2x - 5
y = 2x2
Which slope field is represented by dy/dx = x2?
A puppy gains weight, w, at a rate approximately inversely proportional to its age, t, in months.
A
B
C
D
The particular solution is
What is the value of k in the differential equation (calculator)
Y is proportional to the difference of x and z
y= x-z
y= k(z-x)
y= k(x-z)
y= z-x
y is proportional to the product of z and the square root of x
y=zx2
y=kzx2
y=kzx
y=zkx
∫dx
x+c
2x+c
3x+c
4x+c
Find the mistake if possible:
The Diff EQ is solved correctly
Step 1 is incorrect. The separation of variables wasn't done correctly.
Step 2 is incorrect. They didn't integrate x2 correctly.
Step 3 is incorrect. They didn't take the reciprocal of x3/3+C correctly.
Find f(1) given f'(x)
-12
0
14
20
Evaluate:
4
6
8
10
Find the Particular Solution
y=2+e(2x2+x)
y=2e(2x2+x)
y=ln2x2+x+1+2
y=ln2x2+x+e2
Solve the Initial Value Problem
y=−x1
y=−x2
y=x+1−1
y=x+11
Of the following, which is a solution to the differential equation, select all that apply:
y′′−6y′+8y=0
y=2sin(4x)
y=3e2x
y=Ce4x, where C is a constant
An equation that contains only ordinary derivatives of one or more dependent variables with respect to a single independent variable
Dependent Differential Equation
First Order Differential Equation
Partial Differential Equation
Ordinary Differential Equation
An equation containing derivatives of one or more dependent variables with one or more independent variables?
Partial Equation
Different Equation
Differential Equation
Ordinary Equation
An equation containing partial derivatives of one or more dependent variables of two or more independent variables
Ordinary Partial Differential Equation
Partial Differential Equation
Ordinary Differential Equation
Partially Ordinary Differential Equation
True
False
is a differential equation
is not a differential equation
either ordinary or partial differential equation
neither ordinary of partial differential equation
it is number of the highest degree in a differential equation
variable
degree
order
derivative
The power of the differential equation's highest derivative, after the equation has been made rational and integral in all of its derivatives
order
degree
exponent
variable
which is true?
it is a partial differential equation
it is an ordinary differential equation
it is not a differential equation
it is an equation that cannot be differentiated
when the dependent variable and all of its derivatives are of the first degree, the equation is
non linear
linear
both linear and non linear
none of the options
an equation is non-linear if the coefficients depend at most on the "independent" variables
True
False
in dydx , which is the dependent variable?
x
y
d
secret
in dxdy , the independent variable is
x
y
d
none of the options syempre!
∂y∂x is a partial derivative
Yes
No
neither
Either
Check all ordinary differential equation
dtdx=5x−3
∂y∂x−2=3xy
(x2+y2)dx−2xydy=0
(∂x2∂3W)3=xy∂y2∂2W+∂z2∂2W=0
Check all partial differential equation
dtdx=5x−3
∂y∂x−2=3xy
(x2+y2)dx−2xydy=0
(∂x2∂3W)3=xy∂y2∂2W+∂z2∂2W=0
2. Solve the differential equation
𝑑𝑦/𝑑𝑡 =3𝑡2/𝑦 with initial condition
𝑦(2) = 0.
y=ln∣15t∣
y=16t3
y = 2t3−16
y=2t3−16
Determine the value of "c" that satisfies the differential equation dxdy=y+2x+1 if the curve goes through the point (0, -1).
5/2
-3/2
-1/2
1
Which of the following is the solution to the differential equation dxdy=yx2 with the initial condition y(3) = -2?
y=−2e(−9+3x3)
y=32x3
y=32x3−14
y=−32x3−14
Given the differential equation dP/Dt=5P
A) Find the general solution for P to the differential equation
B)Find the particular solution for P to the differential equation given P(0)= 418
A) P=Ce5t
B) P= 5e418t
A) P=Ce5t
B) P= 418e5t
A) P=Cet
B) P= 418et
A) P=Ce10t
B) P= 418e10t
Solve the following differential equations:
dxdy=cosy1
siny=1+C
siny=x+C
−siny=2x2+C
siny=0+C
Solve the following differential equations:
dxdy=ex
1=ex+C
y=2ex+C
y=ex+C
0=ex+C
Let dxdy=−0.4y and y=5 when x=0 .
What is the solution for y ?
y=5e−0.4x
y=−0.4e5x
y=5e−0.4x
y=0.4e5x
Solve the differential equation dtdy=y3t2 with initial condition 𝑦(2) = 0.
𝑦 = ln(15t)
𝑦 = 16t3
𝑦 = (2𝑡3 − 16)1/2
𝑦 = (2𝑡3 −16)
Degree of Differential equation is
Power of highest order derivative
Highest power
Highest order derivative in DE
None of above
I.F. of dydx+Px=Q is given by:
e∫Pdx
e∫Pdy
e∫Qdy
e∫Qdx
The following Differential Equation is
dxdy=x2y+x
Separable.
Non Separable.
y varies jointly with x and the square of z
y= kxz2
y= kx√z
y= kxz
kx2z
Which choice below represents this slope field?
dy/dx = 2x
dy/dx = -x
dy/dx = x
dy/dx = x2
What is DE
Contains variables
Have constants
Contains variables and its derivatives
Has image
What do mean by linear
Degree 1
Degree 2
Degree 3
Degree 4
What is homogeneous
same degree
same order
different degree
different order
dy/dx = 4x/y. Suppose y(0)=1
The particular solution is
B
C
D
E
An equation containing partial derivatives of one or more dependent variables of two or more independent variables
Ordinary Partial Differential Equation
Partial Differential Equation
Ordinary Differential Equation
Partially Ordinary Differential Equation
Choose the Differential Equations
3x−4y+xy=1
5y+3y′′−x2=1
yx+1=xy
6x3+2y4=xy−4
State the order and degree of this following Differential Equations
(dy3d3x)5+xy=1−x
Order=5
Degree=3
Order=1
Degree=1
Order=1
Degree=0
Order=3
Degree=5
Methods to solve DE are.......................
Integration and Differentiation
Integration and Separable Variable Method
Integrating Factor and Separable Variable Methods
Separable Variable Methods only
State the order of given Differential Equations y(5)
5
1
5 and 1
zero
State TWO types of solutions of Differential Equations
General Solutions Only
General and Particular Solutions
Particular Solutions Only
No solutions
Solve the given DE by using Separable Variable Method
4y3 dy = 2x dx
4y4=x2+c
y4=2x+c
y4=x2+c
34y3=x2+c
Solves this following DE by using Separable Variable Method
y5dxdy=ex
y6=ex+c
6y6=ex+c
y5=xex+c
5y6=xex+c
Given a differential equation as ydxdy=3 and y(0)=1. Find the particular solution of this equation by using Separable Variable Method.
2y2=3x+21
y2=3+21
2y2=3x+c
2y2=33x2+21
IVP stand for.............
Index Value Principle
Initial Value Principle
Initial Value Problem
Index Value Problem
Separate this given variable
(xy+4y)dxdy=1
4y dy = 1−xy dx
y dy=x+4dx
y dy=(x+4)dx
(x+4)dy=ydx
Which of the following differential equations match the graph above?
dxdy=y2−1
dxdy=x2−1
dxdy=y2+1
dxdy=x2+1
Suppose y=f(x) is a particular solution to the differential equation dy/dx=x–y such that f(0)=0. Use the slope field above to estimate the value of f(2).
-2
-1
0
1
Match the following differential equation with the correct slope field: dy/dx=x–y^2.
Shown above is a slope field for which of the following differential equations?
dxdy=1+x
dxdy=x2
dxdy=x+y
dxdy=yx
Which of the following is the solution to the differential equation dy/dx=(x^2)/y with initial condition y(3)=-2?
y=2e3−9+x3
y=−2e3−9+x3
y=32x3
y=32x3−14
y=−32x3−14
Solve the differential equation dy/dx=e^2x in terms of y given the condition that y(0)=0.
y=21e2x+21
y=21e2x−21
y=21e2x+31
y=21e2x−31
y=21ex−21
Solve the differential equation dy/dx=y/1+x^2 in terms of y given the condition that y(0)=1.
y=ln1+x2
y=2ln1+x2
y=e2arctan(x)
y=earctan(x)
y=earctan(2x)
Which of the following is the solution to the differential equation dy/dx=-x/ye^x^2 with initial condition (0,1)? Assume y>0.
e−x2
ex2
e2−x2
e2x2
−e2x2
Find the general solution of the differential equation y’–ysin(x)=0.
∣y∣=Ce−sin(x)
∣y∣=Cesin(x)
∣y∣=Ce−cos(x)
∣y∣=Cecos(x)
∣y∣=−Cecos(x)
Find the general solution of the differential equation dy/dx=2x/4+x^2.
y=arctan(2x)+C
y=21arctan(2x)+C
y=arctan(x2+4)+C
y=ln∣x2+4∣+C
y=2xln∣x2+4∣+C
Find the general solution of the differential equation dy/dx=3y/7x.
y31=Cx71
y3=Cx7
y=Cx71
y71=Cx3
y7=Cx31
Let y=f(t) be a solution to the differential equation dy/dt=ky, where k is a constant. Values of f for selected values of t are given in the table above. Which of the following is an expression for f(t)?
4e2tln3
e(2tln9)+3
2t2+4
4t+4
A rumor spreads among a population of N people at a rate proportional to the product of the number of people who have heard the rumor and the number of people who have not heard the rumor. If p denotes the number of people who have heard the rumor, which of the following differential equations could be used to model this situation with respect to time t, where k is a positive constant?
dtdp=kp
dtdp=kp(N–p)
dtdp=kp(p–N)
dtdp=kt(N–t)
dtdp=kt(t–N)
A puppy weighs 2.0 pounds at birth and 3.5 pounds two months later. If the weight of the puppy during its first 6 months is increasing at a rate proportional to its weight, then how much will the puppy weigh when it is 3 months old?
4.2 Pounds
4.6 Pounds
4.8 Pounds
5.6 Pounds
6.5 Pounds
Population y grows according to the equation dy/dx=ky, where k is a constant and t is measured in years. If the population doubles every 10 years, then the value of k is:
5.000
3.322
0.301
0.200
0.069
During a certain epidemic, the number of people that are infected at any time increases at a rate proportional to the number of people that are infected at that time. If 1,000 people are infected when the epidemic is first discovered, and 1,200 are infected 7 days later, how many people are infected 12 days after the epidemic is first discovered?
343
1343
1367
1400
2057
Bacteria in a certain culture increase at a rate proportional to the number present. If the number of bacteria doubles in three hours, in how many hours will the number of bacteria triple?
ln(227)
ln(29)
ln(2)2ln(3)
ln(2)3ln(3)
ln(2)ln(3)
According to Newton’s law of cooling, the rate at which an object cools (or warms) is directly proportional to the temperature difference between the environment and the object itself. If a pot of boiling water (100°C) is left at room temperature (22°C) and after five minutes the water is only 70°C, find its temperature after another 5 minutes.
51°C
52°C
61°C
62°C
63°C
The population P(t) of a species satisfies the logistic differential equation dP/dt=P(2–P/5000),
Where the initial population P(0)=3000 and t is time in years. What is lim(t->infinity)P(t)?
2500
3000
4200
5000
10000
The number of moose in a national park is modeled by the function M that satisfies the logistic differential equation dM/dt=0.6(1–M/200), where t is the time in years and M(0)=50. What is lim(t->infinity)M(t)?
50
200
500
1000
2000
Which of the following is a separable differential equation?
dtdu+t2u=8
dxdy−6x2y=9x2
xy′−2y−x3cosx=0
dtdθ+2θ=sin t
Solve the differential equation
dxdy+2=2y .y=1+−2x−A4
y=2βex+2
y=1+αe2x
y=1+−4x−A1
Find the general solution of the differential equation
2y dy−(y2+1)cosx dx=0y=Ae(sinx−1)
y=Aesinx−1
y=esinxA−1
y=sinx−1
If
y=γe(αx+β) is the solution for differential equation dxdy=6y , find the values of α, β and γ when y=1, x=2 .α=1, β=0, γ=6
α=6, β=12, γ=6
α=12, β=6, γ=6
α=6, β=−12, γ=1
y=x10x−2
y=9−ln16−x2
y=−x1+219
Which of the following differential equation CAN NOT be separated?
dxdy+1=4x
y2dxdy=xy−2x2y
dxdy+x2y=x+11
dxdy−exy=ex
Do you think Week 3 questions are hard?
Yes
No
Given the curve Ax2 + y2=B is the solution of the differential equations dxdy=− yx , at (2,0) . Find the values of A and B.
A=21, B=41
A=21, B=1
A=1, B=4
A=−1, B=4
Find the general solution for the differential equation dxdy=xy .
y=e2x2+c
y=αe2x2
y=Aex2
y=x2+A1
Given that the acceleration of an object satisfies the differential equation etdtdv=2v . Find the equation of the velocity of the object if it started at v=1.
v=(2−e−t)2
v=(3−2e−t)2
v=(2e−t−1)2
Given the differential equation dtdP=5P
A) Find the general solution for P .
B)Find the particular solution for P to the differential equation given P(0)=418 .
A) P=e5αt
B) P=e418t
A) P=αe5t
B) P=418e5t
A) P=βet
B) P=418et
A) P=αe10t
B) P=418e10t
