1

-5

-1

25

$$-9x^4$$

$$-9x^2$$

$$-9x^4y^2$$

$$-x^2y^4$$

$$x-25y$$

$$x^2-25y^2$$

$$x^2-5y^2$$

$$x^2+5y^2$$

$$x^2+4xy+4y^2$$

$$x^2+4y^2$$

$$x^2-4xy+4y^2$$

$$x^2-4xy+2y^2$$

$$\left(x+3\right)^3$$

$$x^3-27$$

$$x^3+27$$

$$\left(x-3\right)^3$$

$$a^3+b^3=\left(a+b\right)\left(a^2-ab+b^2\right)$$

$$\left(a-b\right)^3=a^3-3a^2b+3ab^2-b^3$$

$$\left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3$$

$$a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)$$

Hai đường chéo bằng nhau.

Hai đường chéo là các phân giác của các góc của hình thoi.

Hai đường chéo cắt nhau tại trung điểm của mỗi đường.

Hai đường chéo vuông góc với nhau.

Hình vuông có hai đường chéo bằng nhau.

Hình vuông là hình chữ nhật nhưng không là hình thoi.

Hình vuông vừa là hình thoi vừa là hình chữ nhật.

Hình vuông có hai đường chéo vuông góc với nhau.

$$\frac{MB}{AB}=\frac{3}{5}$$

$$\frac{MB}{AB}=\frac{5}{2}$$

$$\frac{MB}{AB}=\frac{5}{7}$$

$$\frac{MB}{AB}=\frac{2}{7}$$

4 cm

3 cm

2 cm

1 cm

$$\frac{AE}{EB}=\frac{FA}{FC}$$

$$\frac{EB}{AB}=\frac{FC}{AC}$$

$$\frac{AE}{AB}=\frac{FE}{BC}$$

$$\frac{AE}{BE}=\frac{AF}{CF}$$

$$\left\{-4;\ 25\right\}$$  

$$\left\{\pm2;\ \pm5\right\}$$  

$$\left\{25;\ -25\right\}$$  

$$\left\{5;\ -5\right\}$$  

10 cm

$$\frac{128}{5}cm$$

$$\frac{1}{10}cm$$

$$\frac{45}{2}cm$$

$$\frac{CE}{AE}=\frac{ED}{BE}=\frac{CD}{AB}$$  

$$\frac{CE}{EB}=\frac{ED}{EA}=\frac{DC}{AB}$$  

$$\frac{AB}{CD}=\frac{AE}{ED}=\frac{BE}{CE}$$  

AC = 6cm

CF = 3cm

AC = 9cm

CF = 1,5 cm

6cm

1,5cm

2cm

8cm

4 cm

9 cm

2 cm

Một kết quả khác

2,5

3

4,5

7

5

7

7,5

9

6

5

4

3

7cm

2cm

14cm

0,5cm

x= 1

x= 3

x= -3

x= -1

2x(x - y) - 3y(y- x) = (x - y)(2x - 3y)

5x(x- 3) + x- 3 = (x- 3)(5x - 1)

x2 - 9y2 = (x – 3y) (x + 3y )

(x - 1)3 = x3 - 3x2 + 3x - 1

$$\left(A+B\right)^2=A^2+AB+B^2$$

$$\left(A-B\right)^2=A^2-2AB+B^2$$

$$x^2+2xy+y^2=x^2+y^2$$

$$x^2-2xy+y^2=x^2-y^2$$

$$C^2+2CD+D^2=\left(C-D\right)^2$$

$$\left(x+y\right)^2=\left(x+y\right)\left(x+y\right)$$

$$x^2-y^2=\left(x+y\right)\left(x-y\right)$$

$$\left(-x-y\right)^2=\left(-x\right)^2-2\left(-x\right)y+y^2$$

$$\left(x+y\right)\left(x+y\right)=y^2-x^2$$

$$x^2-4=\left(x-2\right)\left(x+2\right)$$

$$x^2-2x+1=\left(x-1\right)^2$$

$$\left(a+b+c\right)\left(a+b-c\right)=\left(a+b\right)^2-c^2$$

$$2-a=\left(\sqrt{2}+a\right)\left(\sqrt{2}-a\right)$$

$$x-2=\left(\sqrt{x}-\sqrt{2}\right)\left(\sqrt{x}+\sqrt{2}\right)$$

$$\left(c+d\right)^2-\left(a+b\right)^2=\left(c+d+a+b\right)\left(c+d-a+b\right)$$

$$\left(c-d\right)^2-\left(a+b\right)^2=\left(c-d+a+b\right)\left(c-d-a+b\right)$$

$$\left(a+b+c-d\right)\left(a+b-c+d\right)=\left(a+b\right)^2-\left(c-d\right)^2$$

$$\left(c-d\right)^2-\left(a-b\right)^2=\left(c-d+a-b\right)\left(c-d-a-b\right)$$

$$\left(c-d\right)^2-\left(a-b\right)^2=\left(c-d+a-b\right)\left(c-d-a+b\right)$$

$$A^2+2AB-B^2$$  

$$A^2+2AB+B^2$$  

$$A^2-2AB+B^2$$  

$$A^2-2AB-B^2$$  

$$x^2+9$$  

$$x^2+6x+9$$  

$$4x^2-4x+1$$  

$$4x^2+4x-1$$  

$$9-6x+4x^2$$  

$$9+12x+4x^2$$  

$$4x^2-12x+9$$  

$$9-12x+x^2$$  

$$2x^2+x+\frac{1}{2}$$  

$$4x^2+4x+\frac{1}{2}$$  

$$4x^2+2x+\frac{1}{4}$$  

$$2x^2+x+\frac{1}{4}$$  

$$9+4x^2$$  

$$9-4x^2$$  

$$9-12x\ +4x^2$$  

$$9+12x+4x^2$$  

$$\left(x-\frac{1}{2}\right)^2$$  

$$\left(x+\frac{1}{2}\right)^2$$  

$$\left(x-\frac{1}{2}\right)\left(x+\frac{1}{2}\right)$$  

$$x^2-\left(\frac{1}{2}\right)^2$$  

đúng

sai

đúng

sai

(4y+4z)²

(16y+16z)²

(4y+16z)²

(16y+4z)²

(6 + x)²

(x + 36)²

(x + 3)(x + 4)

x(x + 12) - 36

(x + 1)(x - 3)

(x + 3)(x + 1)

(x - 1)(x - 3)

(x + 3)(x - 1)

$$2x^2+x+\frac{1}{2}$$  

$$4x^2+4x+\frac{1}{2}$$  

$$4x^2+2x+\frac{1}{4}$$  

$$2x^2+x+\frac{1}{4}$$  

$$\left(a-b\right)^2$$  

$$\left(a+b\right)^2$$  

$$\left(a+b\right)\left(a-b\right)$$  

$$a^2-2ab+b^2$$  

$$a^2+2ab+b^2$$  

$$a^2+b^2$$  

$$a^2-2ab+b^2$$  

$$a^2-b^2$$  

$$\left(a+b\right)^3$$  

$$\left(a+b\right)\left(a^2-ab+b^2\right)$$  

$$\left(a-b\right)\left(a^2-2ab+b^2\right)$$  

$$\left(a+b\right)\left(a^2+ab+b^2\right)$$  

$$a^3-3a^2b+3ab^2-b^3$$  

$$a^3-b^3$$  

$$\left(a-b\right)\left(a^2+ab+b^2\right)$$  

$$\left(a-b\right)\left(a^2+2ab+b^2\right)$$  

$$a^2-b^2$$  

$$\left(a-b\right)\left(a+b\right)$$  

$$a^2-2ab+b^2$$  

$$a^2+2ab+b^2$$  

$$\left(a-b\right)^3$$  

$$\left(a-b\right)\left(a^2+ab+b^2\right)$$  

$$a^3-3a^2b+3ab^2-b^3$$  

$$\left(a-b\right)\left(a^2-ab+b^2\right)$$  

a.b + a.c - a.d

a.b + c - d

a.b + a.c - d

a.b + a.c + a.d

a.c - b.d

a.(c - d) + b(c - d)

a.c + b.d

$$2x^2-2x$$

$$2x^2-1$$

$$2x-2x$$

$$\left(x-1\right)^2$$

$$\left(x+1\right)^2$$

$$x^2-1$$

$$\left(x-1\right)^2$$

$$\left(x+1\right)^2$$

$$x^2-1$$

$$3x^2−6x−3$$  

$$3x^2−6x+3$$  

$$3x^2+6x−3$$  

$$3x^2+6x+3$$  

$$2x^3-6x^2+8x$$

$$2x^3+6x^2-8x$$

$$2x^3+6x^2-8$$  

$$2x^3-6x^2+8x$$  

$$3x^2−6x−3$$  

$$3x^2−6x+3$$  

$$3x^2+6x−3$$  

$$3x^2+6x+3$$  

$$2x^3-6x^2+8x$$

$$2x^3+6x^2-8x$$

$$2x^3+6x^2-8$$  

$$2x^3-6x^2+8x$$  

$$8x^2-6x^2y+4x$$  

$$6x^2+8x^2y-4x$$

$$6x^2+8x^2y-4x$$

$$6x^2-8x^2y+4x$$

$$\frac{3}{5}x^2-\frac{2}{5}x^2y\ +\frac{6}{5}y^2x$$  

$$\frac{3}{10}x^2-\frac{2}{5}x^2y\ +\frac{6}{5}y^2x$$  

$$\frac{3}{10}x^2+\frac{2}{5}x^2y\ +\frac{6}{5}y^2x$$  

$$\frac{3}{10}x^2-\frac{2}{5}x^2y\ -\frac{6}{5}y^2x$$  

$$5x^3−7x^2y+2xy^2+5x−2y$$  

$$5x^3+7x^2y+2xy^2+5x−2y$$  

$$5x^3−7x^2y-2xy^2+5x−2y$$  

$$5x^3−3x^2y+2xy^2+5x−2y$$  

  $$x^2+2xy+y^2$$  

$$x^2+xy+y^2$$  

$$x^2-xy+y^2$$  

$$2x+2xy+2y$$  

$$x^2+y^2+x^2y$$  

$$x^2-y^2$$  

$$x^2+y^2$$  

$$x^2+y^2-x^2y-xy^2$$  

$$x^2-8$$  

$$x^2-2x+15$$  

$$x^2-2x-15$$  

$$x^2-2x$$  

$$x^2-1$$  

$$x^2+1$$  

1

$$x^3-1$$  

nằm trên một đường thẳng.

nằm trên một đoạn thẳng.

nằm trên một mặt phẳng.

nằm trên hai đường thẳng.

$$180^0$$  

$$360^0$$  

$$90^0$$  

$$100^0$$  

cắt nhau

song song

chéo nhau

trùng nhau

$$90^0$$  

$$180^0$$  

$$360^0$$  

$$260^0$$  

$$90^0$$  

$$180^0$$  

$$360^0$$  

$$260^0$$  

$$x=1$$  

$$x=\frac{2}{3}$$  

$$x=-\frac{2}{3}$$  

$$x=3$$  

$$x=-\frac{1}{3}$$  

$$x=\frac{1}{3}$$  

$$x=3$$  

$$x=-3$$  

$$x=3$$  

$$x=−4$$  

$$x=−5$$  

$$x=5$$