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WorksheetsPrecalculus Semester 1 Final Study
Total questions: 100
Worksheet time: 3hrs 24mins
f(x) = 2x - 8 and
g(x) = 4x
and g(x) = x - 2
Find f(g(5))
Find f(h(5)) based on the graphs of f(x) and g(x)
-6
-3
6
2
and h(x) = x3+1,
find j(h(x)).
its inverse, f-1(x) =
then solving for x
Find g(f(2))
-4
-2
0
4
Find f(g(4))
1
-2
-3
-4
Find f(g(−1))
(a)
Find g(f(6))
(a)
Find f(g(−1))
-7
-4
0
2
Find g(f(1))
-7
-1
0
2
Find g(f(−1))
(a)
Find f(g(−2))
(a)
Find g(f(0))
(a)
Find f(g(−2))
(a)
Find the inverse of f(x)=3x+2
f−1(x)=3x−2
f−1(x)=2+3x
f−1(x)=3x−2
Find the inverse of f(x)=2x+1
f−1(x)=2x
f−1(x)=2x−1
f−1(x)=2
Find the inverse of f(x)=4x
f−1(x)=4x
f−1(x)=4
f−1(x)=41
Find the inverse of f(x)=3x−5
f−1(x)=53+x
f−1(x)=3x+5
f−1(x)=5x+3
Find the inverse of f(x)=10+7x
f−1(x)=10x−7
f−1(x)=7x−10
f−1(x)=10+7x1
The inverse of f(x)=8x+30 is f−1(x)=308 .
True
False
The inverse of f(x)=x2−1 is f−1(x)=(x+1)21 .
True
False
The notation for an inverse is
f−1(x)
g−1(x)
All of the above
are these inverse functions?
no
yes
no way to tell
1st you replace f(x) with y
2nd switch the x's and y's
What do you do next?
Find the exact value of cos−1(23)
−3π
3π
−6π
6π
Find the exact value of sec−1(−2)
32π
−3π
34π
−32π
Q1. The principal value of Sin−1(21) is
4π
6π
2π
Q2. The principal value of Sin−1(21) is
6π
−4π
−3π
Q3. The principal value of Tan−1(−1) is
−4π
−3π
−6π
Which equation is true?
sin (x) = 6/8
cos (x) = 8/6
cos (x) = 6/8
tan (x) = 6/8
Which equation would you use to solve for the unknown angle?
x = sin–1(4/5)
x = cos–1(4/5)
x = cos–1(5/4)
x = tan–1(4/5)
Solve for x.
x = 90º
x = 60º
x = 45º
x = 30º
Evaluate: cos-1(√3/2)
π/3
2π/3
π/6
5π/6
cosθ = - √(3)/2
on θ∈[0, 2π)
Solve for 0≤x≤2π
4cos2x - 2 = 0
π/3, 5π/3
π/4, 7π/4
3π/4, 5π/4
π/6, 11π/6
Solve for 0≤x≤2π
tanx = 1
π/2, π
π/4, 3π/4
π/4, 5π/4
3π/4, 7π/4
Which of the following is NOT
a solution to
tan θ = 0 ?
θ = 0
θ = π /2
θ = π
θ = 2π
Find all solutions to the equation sinθ = .6 . You answer should be in degrees. Consider n to be any integer
36.9° and 143.1°
36.9° + 360°n
36.9° + 2πn and 143.1° +2πn
36.9° + 360°n and 143.1° + 360n
Find all solutions to cosθ = −.3 for 0<θ<2π . Your answer should be in radians. Assume n is any integer. Check all answers that apply.
4.408 + 2πn
1.266
1.875
1.875 +2πn
4.408
Find all solutions for 2sin(6x) + √3 = 0.
Your answer should be in radians.
x = .175 + πn/3 and x = .873 + πn/3
x = 1.920 + 2πn and x = 1.222 + 2πn
x = .698 + πn/3 and x = .873 + πn/3
x = 4.189 + 2πn and x = 5.236 + 2πn
Find all solutions for 2cos(3πx) + 5 = 4 .
Your answer should be in radians.
x = .278 + 2n/3 and x = .611 + 2n/3
x = .111 + 2n/3 and x = .556 + 2n/3
x = .222 + 2πn and x = .444 + 2πn
x = .222 + 2n/3 and x = .444 + 2n/3
Use Sum or Difference Identities to find the exact value of each expression.
cos(75°)
1/4
cos70ocos40o−sin70osin40o is equivalent to
cos30o
cos70o
cos110o
sin70o
If sinA=54,tanB=125, and A and B are first quadrant angles, what is the value of sin(A+B) ?
6563
−6533
6533
−6563
If sinθ=35 , then cos2θ equals
31
−31
91
−91
Find the exact value of tan 12π
2−3
−2+3
3
33
i2=?
i
-1
-i
1
i63 =?
i
-1
-i
1
-3i(4 + 2i)
(2 - 3i)(5 + 4i)
i7
Simplify.
(a)
What is the real portion of the number
3+5i3
5
-3
-5
What is the imaginary portion of the number −7−12i
7
12
−7
−12
Two complex numbers are added. How do we do this?
We add up all 4 numbers you see.
We add up all the big numbers.
We add only the real parts. Because we cannot see the imaginary parts.
We add the real parts together, and then separately add the imaginary parts together. Your final answer is in the form. a+bi
Simplify the expression:
(1 + 5i) + (1 − 5i)
2 + 10i
2 + 10i2
2
−8
Simplify the expression:
(8 + 9i) + (4 − 6i)
17 + 3i
12 + 3i2
17 −2i
12 + 3i
Simplify the expression:
(5 + 14i) − (10 + 2i)
5 −16i
−5 + 16i
5 − 12i
−5 + 12i
2(3 + 4i)−(4 − 6i)
2 + 14i
10 + 2i
−1 −2i
−2 −2i
Determine the modulus of : ∣3−2i∣
−13
−1
13
5
What is the correct set-up to find the absolute value of -9+5i?
−9+5
(−9+5i)2
(−9)2+(5)2
−9+5
-2 + 5i
6 + 2i
4 ( cos π /3 + i sin π /3)
4 ( cos π /3 + i sin π /3)
f(x)= x5 - 3x3 + x
Which of these is a possible rational root of the polynomials?
x3 - 6x2 - x + 30
0
4
-9
-15
y = 4x6 - 12x5 - x4 + 2x3 - 6x2 - 5x + 10
(x - 5) is one factor.
