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Worksheets

Logarithm (Concluding part)

Total questions: 20

Worksheet time: 56mins

Name
Class
Date
1.

Condense to a single logarithm.

a)

ln x4/ y

b)

ln xy4

c)

ln x/ y4

d)

ln x4/ y4

2.
Solve:
log9(x)+log9(x+2)=log9(35)
a)
5
b)
-7
c)
5, -7
d)
-7, -13
3.
log5(4x-7)=log5(x+5)
a)
3
b)
12
c)
4
d)
7
4.

Simplify the following: log5(3)+log5(r)log5(w)\log_5\left(3\right)+\log_5\left(r\right)-\log_5\left(w\right)  

a)

log5(3rw)\log_5\left(3rw\right)  

b)

log5(3+rw)\log_5\left(3+r-w\right)  

c)

log5(3rw)\log_5\left(\frac{3r}{w}\right)  

d)

log5(3r)log5(w)\frac{\log_5\left(3r\right)}{\log_5\left(w\right)}  

5.

Expand the following: log(j4k7)\log\left(j^4k^7\right)  

a)

log(4j)+log(7k)\log\left(4j\right)+\log\left(7k\right)  

b)

11log(j+k)11\log\left(j+k\right)  

c)

28log(jk)28\log\left(jk\right)  

d)

4log(j)+7log(k)4\log\left(j\right)+7\log\left(k\right)  

6.

Use Logarithm table to evaluate 0.5915317.82\frac{\sqrt[3]{0.5915}}{17.8^2} (2005 NEC0)

a)

2.64938 ×1032.64938\ \times10^{-3}

b)

0.00265

c)
0.00089
d)
0.00234
7.

Evaluate using logarithm tables. 3.873 +203.873 20\frac{3.87^{3\ }+20}{3.87^3\ -20}

a)

2.054

b)

2.05

c)

2.0

d)

2

8.

Evaluate using Logarithm tables : 1.4873  11.4873 + 1\frac{1.487^3\ -\ 1}{1.487^3\ +\ 1}

a)

0.5338

b)

0.534

c)

0.532

d)
0.678
9.

Express the square root of 0.000144 in standard form.

a)

1.2 × 1041.2\ \times\ 10^{-4}

b)

1.2 × 1031.2\ \times\ 10^{-3}

c)

1.2 × 1021.2\ \times\ 10^{-2}

d)

1.2 × 1061.2\ \times\ 10^{-6}

10.

Which of these statements about y=8 m  is correct ?y=8\ \sqrt[]{m}\ \ is\ correct\ ?

a)

log y=log8×log m\log\ y=\log8\times\log\ \sqrt[]{m}

b)

log y=3log2 × 12log m\log\ y=3\log2\ \times\ \frac{1}{2}\log\ m

c)

log y=3log2  12log m\log\ y=3\log2\ -\ \frac{1}{2}\log\ m

d)

log y= 3log2 + 12log m\log\ y=\ 3\log2\ +\ \frac{1}{2}\log\ m

11.

Solve the logarithmic equation : log5 (x29)=0\left(x^2-9\right)=0

a)
5
b)
-5
c)
0
d)
√10, -√10
12.

Solve the equations : log(x2+6x)=1.4314\log\left(x^2+6x\right)=1.4314

Note: The question should be changed to indices as x2 + 6x = 101.4314

The value of 101.4314 is same as the antilog of 1.4314.

a)

9 or -3

b)

-9 or 5

c)

-9 or 3

d)

5 or 9

13.

If log10 x=2.7087, find xx=\overline{2}.7087,\ find\ x

a)

0.01866

b)

0.02913

c)

0.05113

d)
128.0
14.

Given that 2x y2yx=6, find the ratio x:y\frac{2x\ -y}{2y-x}=6,\ find\ the\ ratio\ x:y

a)
13:8
b)
15:10
c)
10:5
d)
12:7
15.

Evaluate 102.6457

Note: This is the same as finding the antilog of 2.6457

a)
400.1
b)
512.3
c)

442.3

d)
350.5
16.

In changing the base of the logarithm logef, which of these is correct?

a)

logfe

b)

logfe1\frac{\log_fe}{1}

c)

Both b and d

d)

1logfe\frac{1}{\log_fe}

17.

What is the value of logaa4 ?

a)

1

b)

2

c)

4

d)

a

18.

Given that loga2=0.693 and loga3=1.097, find loga13.5.\log_a2=0.693\ and\ \log_a3=1.097,\ find\ \log_a13.5.

a)

1.404

b)

1.790

c)

2.598

d)

2.790

19.

Evaluate using logarithm tables : (26.795625)\left(\sqrt[5]{\frac{26.7}{9562}}\right)

a)

0.4561

b)

0.3084

c)
0.582
d)
0.215
20.

Simplify this logarithm with bar notation : 3.8 ÷ 4\overline{3}.8\ \div\ 4

a)
0.75
b)

2.2\overline{2}.2

c)

1.45\overline{1}.45

d)

0.95\overline{0}.95