
7.4 Side Splitter Theorem
Flashcard
•
Mathematics
•
9th - 10th Grade
•
Practice Problem
•
Hard
+3
Standards-aligned
Wayground Content
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15 questions
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1.
FLASHCARD QUESTION
Front
What does the Side Splitter Theorem state?
Back
If a line is parallel to one side of a triangle and intersects the other two sides, then the ratios of the lengths of the segments created on those sides are equal.
Tags
CCSS.HSG.SRT.B.4
2.
FLASHCARD QUESTION
Front
In the context of the Side Splitter Theorem, if a line divides two sides of a triangle into segments of lengths AB and BC, what is the relationship expressed by the theorem?
Back
The relationship is expressed as \( \frac{AB}{BC} = \frac{AE}{ED} \) where AE and ED are segments on the third side.
Tags
CCSS.HSG.SRT.B.4
3.
FLASHCARD QUESTION
Front
What is the definition of similar figures?
Back
Two figures are similar if they have the same shape but not necessarily the same size, meaning their corresponding angles are equal and their corresponding sides are in proportion.
Tags
CCSS.8.G.A.2
CCSS.HSG.CO.B.6
4.
FLASHCARD QUESTION
Front
If two triangles are similar, what can be said about their corresponding sides?
Back
The lengths of their corresponding sides are proportional.
Tags
CCSS.8.G.A.2
CCSS.HSG.CO.B.6
5.
FLASHCARD QUESTION
Front
How can you find the missing length in a triangle using the Side Splitter Theorem?
Back
You can set up a proportion based on the lengths of the segments created by the parallel line and solve for the missing length.
Tags
CCSS.HSG.CO.C.9
6.
FLASHCARD QUESTION
Front
What is the significance of parallel lines in the Side Splitter Theorem?
Back
Parallel lines create proportional segments on the intersected sides of the triangle, which is the basis for the theorem.
Tags
CCSS.HSG.SRT.B.4
7.
FLASHCARD QUESTION
Front
If a triangle has sides of lengths 10 and 15, and a line parallel to one side creates segments of lengths 4 and x on the other two sides, how do you find x?
Back
Set up the proportion \( \frac{10}{15} = \frac{4}{x} \) and solve for x.
Tags
CCSS.HSG.SRT.B.4
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