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Discriminant & Solving Quadratics

Discriminant & Solving Quadratics

Assessment

Presentation

Mathematics

9th - 12th Grade

Medium

CCSS
HSA-REI.B.4B, HSN.CN.C.7

Standards-aligned

Created by

Jessica Peters

Used 15+ times

FREE Resource

12 Slides • 12 Questions

1

Discriminant & Solving Quadratics

Unit 4: Factoring & Solving Polynomials

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2

Open Ended

Warm-Up: The height of a ball thrown into the air is represented by the function:

 h(t)=16t2+30t+6h\left(t\right)=-16t^2+30t+6 

 Find the roots and determine what they represent. Round to the nearest hundredth. 

3

Quadratic Equations

Sometimes, we only need to know what TYPE of solutions a quadratic has, not the answers themselves.

Which part of the quadratic formula will determine what type of answers the quadratic has? (Real: rational or irrational; Imaginary)



 x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  

4

The DISCRIMINANT

 b24acb^2-4ac  is called the discriminant (notice there is NO square root)
The discriminant is a value that can tell us the nature of the roots of a quadratic: 2 real roots (crosses the x-axis twice), 2 imaginary roots (never touches the x-axis), or 1 real root (touches the x-axis once).

The discriminant tells us whether the roots are real or imaginary, and more specifically wheter the REAL roots are rational or irrational. 

5

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6

Discovering the DISCRIMINANT

I am going to number you off from 1-4. 1s solve #1, 2s solve #2, 3s solve #3, 4s solve #4. Be ready to tell me the discriminant & the roots. 


 1.  x2+10x+25=01.\ \ x^2+10x+25=0  
 2.  2x25x3=02.\ \ 2x^2-5x-3=0  
 3.  3x211x+2=03.\ \ 3x^2-11x+2=0  
 4.  x2 18x+82=04.\ \ x^{2\ }-18x+82=0  

7

Discovering the DISCRIMINANT


 1.  x2+10x+25=01.\ \ x^2+10x+25=0  
Discriminant: 0       Root: -5
*If the discriminant is 0, you will have ONE, REAL, RATIONAL root. 

 2.  2x25x3=02.\ \ 2x^2-5x-3=0  
Discriminant: 49    Roots:   12, 3-\frac{1}{2},\ 3  
*If the discriminant is a perfect square, you will have TWO, REAL, RATIONAL roots. 

8

Discovering the DISCRIMINANT


 3.  3x211x+2=03.\ \ 3x^2-11x+2=0  
Discriminant: 97    Roots:  11±976 3.47, 0.19\frac{11\pm\sqrt{97}}{6}\approx\ 3.47,\ 0.19  
*If the discriminant is not a perfect square, you will have TWO, REAL, IRRATIONAL roots. 

 4.  x2 18x+82=04.\ \ x^{2\ }-18x+82=0  
Discriminant: -4    Roots:  9±i9\pm i  
*If the discriminant is negative, you will have TWO, IMAGINARY roots.

9

Multiple Choice

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Determine the number and nature of the roots.

1

1 real, rational root

2

2 real, rational roots

3

2 real, irrational roots

4

2 imaginary roots

10

Multiple Choice

Question image

Determine the number and nature of the roots.

1

1 real, rational root

2

2 real, rational roots

3

2 real, irrational roots

4

2 imaginary roots

11

Multiple Choice

Question image

Determine the number and nature of the roots.

1

1 real, rational root

2

2 real, rational roots

3

2 real, irrational roots

4

2 imaginary roots

12

Multiple Choice

When the discriminant is _________, the quadratic will have 1, real, rational root.

1

zero

2

positive perfect square

3

positive non-perfect square

4

negative

13

Solving Quadratics

20) Notes

There are four methods for solving quadratics:

*Factoring

*Quadratic Formula

*Completing the Square

*Square Root

14

Solving by Factoring:

Get the equation equal to zero. Factor the quadratic. Then, set each factor equal to zero and solve.

15

Multiple Choice

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Solve the equation by factoring.

1

x=4, 65x=4,\ \frac{6}{5}

2

x=4, 65x=4,\ -\frac{6}{5}

3

x=4, 65x=-4,\ \frac{6}{5}

4

x=4, 65x=-4,\ -\frac{6}{5}

16

Solving by Quadratic Formula:

Get the equation equal to zero. Identify a, b, and c. Use the formula to find the roots. 


 x=b±b24ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  

17

Multiple Choice

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Solve the equation using the quadratic formula.

1

x=3±6910x=\frac{-3\pm\sqrt{69}}{10}

2

x=6±26920x=\frac{6\pm2\sqrt{69}}{-20}

3

x=3±5110x=\frac{-3\pm\sqrt{51}}{10}

4

x=6±25120x=\frac{6\pm2\sqrt{51}}{-20}

18

Solving by Completing the Square:

1. Isolate c on the right side of the equation. 

2. Complete the square by adding  (b2)2 \left(\frac{b}{2}\right)^{2\ }  to both sides. 
3. Factor the left, simplify the right. 

4. Solve for x. 

19

Multiple Choice

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What is the first step in solving this equation by completing the square.

1

Subtract 84 from both sides

2

Add 84 to both sides

3

Add 8 to both sides

4

Complete the square

20

Multiple Choice

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What will we add to both sides to "complete the square"?

1

2

2

4

3

-2

4

-4

21

Multiple Choice

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In the third step, what does the left side factor into?

1

(x+4)2\left(x+4\right)^2

2

(x4)2\left(x-4\right)^2

3

(x+2)2\left(x+2\right)^2

4

(x2)2\left(x-2\right)^2

22

Multiple Choice

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Find the solutions. Simplify!

1

 x=2±88x=-2\pm\sqrt{-88}  

2

 x=2±222x=-2\pm2\sqrt{22}  

3

 x=1±22x=-1\pm\sqrt{22}  

4

 x=2±222ix=-2\pm2\sqrt{22}i  

23

Solving by Taking Square Roots:

Isolate the squared quantity first. Then, square root both sides to begin solving for x. Don't forget ±\pm !


*This method only works when  b=0b=0  

24

Multiple Choice

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Solve the equation using the square root method. Simplify!

1

 78\frac{7}{8}  

2

 ±78\pm\frac{7}{8}  

3

 ±4964\pm\sqrt{\frac{49}{64}}  

4

 4964\frac{49}{64}  

Discriminant & Solving Quadratics

Unit 4: Factoring & Solving Polynomials

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