

Momentum
Presentation
•
Science
•
11th Grade - University
•
Practice Problem
•
Easy
+4
Standards-aligned
Brittany Backofen
Used 9+ times
FREE Resource
28 Slides • 20 Questions
1
Momentum
and impulse!
and collisions!
and explosions!

2
3
Units for momentum are kg*m/s
4
Multiple Choice
What does m stand for?
muscle
mass
momentum
meters
5
Multiple Choice
What does v stand for?
velocity
volume
variable
voltage
6
Multiple Choice
What does p stand for?
momentum
particle
pressure
pounds
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8
9
Poll
Which one would have more momentum?
Butterfly
Truck
Neither
Both
10
Any of those answer choices could be correct!
While the masses are obviously very different, there is no information given about the velocity
If the truck is not moving, but the butterfly is, the butterfly would have more momentum (vice versa for the truck)
If the butterfly and the truck were both moving, it would depend on their velocities
11
The "P" should be lowercase.
12
Multiple Choice
What does F stand for?
force
friction
fulcrum
faux pas
13
Multiple Choice
What does t stand for?
temperature
time
period
torque
14
Multiple Choice
What does J stand for?
impulse
jerk
jolt
junk
15
16
Open Ended
Describe how to find the impulse on a graph and which type of graph you use to evaluate impulse.
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21
Multiple Select
This type of collision conserves momentum (you can select more than one).
Elastic
Inelastic
Perfectly inelastic
22
Multiple Select
This type of collision conserves kinetic energy (you can select more than one).
elastic
inelastic
perfectly inelastic
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29
The inelastic collision is just opposite. Instead of sticking together, it separates.
30
Solve the problem on this slide and enter your answers on the next few slides. You will need the momentum of both objects before and after the collision.
31
Fill in the Blank
Type answer...
32
Fill in the Blank
Type answer...
33
Fill in the Blank
Type answer...
34
Fill in the Blank
Type answer...
35
Fill in the Blank
Type answer...
36
Problem worked out:
Total momentum of the system before = total momentum after
mass x velocity of grandma = 480 (before)
mass x velocity of baby = 0 (before)
total momentum before the collision = 480 kg*m/s
This was an inelastic collision, the two objects stuck together, so you have to add the masses. The momentum after the collision still has to remain the same
mass x velocity = momentum (after), so 120 kg x velocity = 480
Velocity of the system after the collision = 4 m/s
37
Solve the problem on this slide and enter your answers on the next few slides. You will need the momentum of both objects before and after the collision.
38
Fill in the Blank
Type answer...
39
Fill in the Blank
Type answer...
40
Fill in the Blank
Type answer...
41
Fill in the Blank
Type answer...
42
Fill in the Blank
Type answer...
43
Problem worked out:
Total momentum of the system before = total momentum after
mass x velocity of left train = 20 (before)
mass x velocity of right train = 0 (before)
total momentum before the collision = 20 kg*m/s
This was an inelastic collision, the two objects stuck together, so you have to add the masses. The momentum after the collision still has to remain the same
mass x velocity = momentum (after), so 5m x velocity = 20
Velocity of the system after the collision = 4 m/s
44
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48
I'm not going to ask you to mathematically solve the center of mass for an object
Just know that when we are evaluating momentum and KE, we are looking at these objects moving in a straight line. We are solving them based on their center of mass.... but these conservation laws will also be true when the object begins to turn about its center of mass in the next unit....
Momentum
and impulse!
and collisions!
and explosions!

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