How to construct a Frequency Distribution Table?

How to Construct a Frequency Distribution Table?

Elizabeth Borres

Unit Test Tomorrow!!!

(Basic Terms, Levels of Measurement)

At the end of the lesson, students will be able to:

-Construct a FDT.

Multiple Choice

A collection of observation produced by sorting them into classes and showing their frequency of occurrence in each class.

• Statistics table

• Frequency distribution table

• Distribution column

• Frequency Graph

Multiple Choice

Which of the following statements corresponds to a frequency distribution?

• a table that shows the number of times a data entry appears in a data set.

• a data set that shows the number of data entries that appear in a time.

• a conclusion drawn from a sample.

• the boundaries between two consecutive bars.

Multiple Choice

Which pet was chosen by 6 people?

• Cat

• Goldfish

• Hamster

• Snake

Multiple Choice

Which are the least popular pets?

• Cats and dogs

• Goldfish and budgie

• Lizard and snake

• Hamster and rabbit

Multiple Choice

Which is the most popular pet?

• Dog

• Cat

• Hamster

• Rabbit

How to construct a Frequency Distribution Table?

(Follow the steps carefully)

Step 1

Decide on the number of classes.

number of classes (k)

(Usually it is given in the problem)

Multiple Choice

What do you mean by k in the formula?

• tally

• class interval

• number of classes

• score

Multiple Choice

Based on the table, what is the number of classes (k)?

• 5

• 10

• 15

• 20

Multiple Select

What is the highest and lowest number in the table? Check both.

• 16

• 17

• 63

• 64

• 66

Step 2

Determine the class interval.

class interval (c.i.) or width (w)

Multiple Choice

Is class interval different from the class width?

• yes

• no

Step 2

Determine the class interval (c.i.) or width (w).

 $c.i.=\frac{highest\ score\ -\ lowest\ score}{number\ of\ classes}$ 

 $or\ c.i.\ =\ \frac{HS\ -LS}{k}$  

Multiple Choice

 $c.i.=\frac{HS\ -\ LS}{k}$ , use the formula to find for the class interval. 

•   $8.4\approx8$  

•  $9.4\approx9$  

•  $10.4\approx10$  

•  $11.4\approx11$  

 $c.i.\ =\ \frac{64\ -\ 17}{5}\ =\ \frac{47}{5}=9.4\approx9$  

c.i. = 9

Step 3

Set the individual class limit.

(Start from the lowest number)

 $Lowest\ number\ +c.i.\ -\ 1\$  
 $17+9-1=25$  

First class is
17 - 25

 $Lowest\ number\ +c.i.\ -\ 1\$  
 $17+9-1=25$  

Step 4

Tally the observation into the appropriate classes 

and count the number of tallies in each class.