Unit 8 Test Review

Unit 8 Test Review

What are the two factors in the denominator?

Multiple Select

What are the two factors in the denominator?

• x

• x-5

• x+5

• x-2

• x+2

Open Ended

How do we find the factors in the denominator?

Open Ended

What are some vocabulary we just used?

Open Ended

How do we find the vertical asymptotes?

Open Ended

How do we find the horizontal asymptote?

Multiple Select

What will we be multiplying by to solve for x?

 $\frac{x+1}{3\left(x-2\right)}=\frac{5x}{6}+\frac{1}{x-2}$  

• x+1

• 5x

• 6

• 3

• x-2

 $\frac{x+1}{3\left(x-2\right)}=\frac{5x}{6}+\frac{1}{x-2}$  

Fill in the Blank

What are we going to do to find the solutions?

 $0=5x^2-12x+4$  

Fill in the Blank

What are the two factors of:

 $0=5x^2-12x+4$  

 $0=5x^2-12x+4$  

Fill in the Blank

What are our solutions if:

 $0=\left(x+2\right)\left(5x+2\right)$  

Fill in the Blank

What are our restrictions?

 $\frac{x+1}{3\left(x-2\right)}=\frac{5x}{6}+\frac{1}{x-2}$  

 $\frac{x+1}{3\left(x-2\right)}=\frac{5x}{6}+\frac{1}{x-2}$  

Open Ended

What does this mean for our solutions we found?

 $x=2\ and\ x=\frac{2}{5}$  

 $x=\frac{2}{5}$  

Fill in the Blank

Find the solution of the following:

 $-\frac{2}{x+3}+\frac{4}{x-2}=\frac{1}{x-2}$  

 $-\frac{2}{x+3}+\frac{4}{x-2}=\frac{1}{x-2}$  

 $-\frac{2}{x+3}+\frac{4}{x-2}=\frac{1}{x-2}$  

Fill in the Blank

What is the first thing we do to solve this problem?

 $\frac{x}{x^2-5x+6}-\frac{3}{x-3}=\frac{3}{x-2}$  

Fill in the Blank

What are the factors of:

 $x^2-5x+6$  

 $x^2-5x+6$  

 $\frac{x}{\left(x-2\right)\left(x-3\right)}-\frac{3}{x-3}=\frac{3}{x-2}$  

Fill in the Blank

What are we going to multiply by?

 $\frac{x}{\left(x-2\right)\left(x-3\right)}-\frac{3}{x-3}=\frac{3}{x-2}$  

Multiply by (x-2)(x-3)!

Fill in the Blank

What do we get when we multiply by (x-2)(x-3)?

 $\frac{x}{\left(x-2\right)\left(x-3\right)}-\frac{3}{x-3}=\frac{3}{x-2}$  

Fill in the Blank

What are our restrictions?

 $\frac{x}{\left(x-2\right)\left(x-3\right)}-\frac{3}{x-3}=\frac{3}{x-2}$  

 $\frac{x}{\left(x-2\right)\left(x-3\right)}-\frac{3}{x-3}=\frac{3}{x-2}$  

Open Ended

What does this mean for our solution we found?

 $x=3$  

No Real Solutions

Fill in the Blank

Find the solution to the following:

 $\frac{x+5}{x^2+x}=\frac{1}{x^2+x}-\frac{x-6}{x+1}$  

 $\frac{x+5}{x^2+x}=\frac{1}{x^2+x}-\frac{x-6}{x+1}$  

 $0=x^2-5x+4$  

Open Ended

What is our first step when solving?

Open Ended

What do we multiply the fractions by?

Open Ended

When we have x squared after multiplying what extra step are we going to have to do?

Open Ended

How do we find our restrictions?

Open Ended

What happens if the restrictions are the same as the solutions?

Fill in the Blank

What are the transformations of:

 $y=\frac{-1}{x+2}+3$  

 $y=\frac{-1}{x+2}+3$  

Open Ended

How do we find the horizontal asymptote?

Fill in the Blank

What is the horizontal asymptote?

Open Ended

How do we find the vertical asymptote?

Fill in the Blank

What is the vertical asymptote?

 $y=\frac{-1}{x+2}+3$  

Domain

 $y=\frac{-1}{x+2}+3$  

Range

Multiple Choice

Does the graph have Rotational Symmetry around the point (-2,3)?

• yes

• no

Lindsey and Fran have volunteered to contact every member of their organization by phone to inform them of an upcoming event. Fran can complete the calls in six days if she works alone. Lindsey can complete them in four days. How long will they take to complete the calls working together?

Fill in the Blank

Jennifer can do a particular job in 4 hours. It takes Mikaela 6.5 hours to do the same job. How long will it take them to complete the job if they work together?

Jennifer can do a particular job in 4 hours. It takes Mikaela 6.5 hours to do the same job. How long will it take them to complete the job if they work together?