
WORK2
Presentation
β’
Science
β’
8th Grade
β’
Practice Problem
β’
Easy
Annie Rose Baylon
Used 1+ times
FREE Resource
13 Slides β’ 1 Question
1
2
βWORK DONE
NO WORK DONE
3
βWORK DONE
NO WORK DONE
βWHO LOSE ENERGY?
WHO GAIN ENERGY?
4
βWork is a way of transferring energy.
Energy is the capacity to do work.
When work is done BY an object it loses energy and when work is done ON an object it gains energy. Another concept related to work and energy is power.
5
Power is the rate of doing work or the rate of using energy.
In equation,
π = ππππ /π‘πππ or
P = πΈπππππ¦ /π‘ππe
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Power is the rate of doing work or the rate of using energy.
In equation,
π = ππππ /π‘πππ or
P = πΈπππππ¦ /π‘ππe
The conversion of unit from joules per second to watts is:
1 π€ππ‘π‘ = 1 πππ’ππ /1 π ππππd
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Power(watts)
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βSample problem:
What is the power output of the stickman that pushes the box 5 meters in 3 seconds with a constant force of 12 N?
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βSample problem:
What is the power output of the stickman that pushes the box 5 meters in 3 seconds with a constant force of 12 N?
Given:
5 m= d
3 s= t
12N=F
10
βSample problem:
What is the power output of the stickman that pushes the box 5 meters in 3 seconds with a constant force of 12 N?
Given:
5 m= d
3 s= t
12N=F
Find:
W=?
11
βSample problem:
What is the power output of the stickman that pushes the box 5 meters in 3 seconds with a constant force of 12 N?
Given:
5 m= d
3 s= t
12N=F
Find:
W=?
Formula:
P= W/t
Final answer:
P=20 watts
Solution:
P=W/t
P=Fd/t
P=12N(5m)/3s
P=20Nm/s
12
βSample problem:
What is the power output of the stickman that pushes the box 5 meters in 3 seconds with a constant force of 12 N?
Given:
5 m= d
3 s= t
12N=F
Find:
W=?
​Formula: P= W/t Solution: P=W/t P=Fd/t P=12N(5m)/3s P=20Nm/s Final answer: P=20 watts
13
Draw
What is the power output if 15N of force was applied on an object at an angle of 25Β° above the horizon to move an object 4meters horizontally in 4 seconds.
14
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