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AP CHEM Unit 6 Day 1 Review

Authored by Patrick Boylan

Chemistry

11th Grade

Used 144+ times

AP CHEM Unit 6 Day 1 Review
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11 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

When the chemical reaction A + B ⇄ C + D is at equilibrium, 
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all four concentrations are equal.
the reverse reaction has stopped. 
the forward reaction has stopped.
neither the forward nor the reverse reactions have stopped.

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Write the general equilibrium constant for
2 NaBr(aq) + Pb(ClO4)2(aq) ⇄ PbBr2(s) + 2 NaClO4(aq)
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3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Write the equilibrium expression for the reaction
SbCl5(g) ⇄ SbCl3(g) + Cl2(g)
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4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

Write the reaction quotient for
Li2CO3(s) ⇄ Li2O(s) + CO2(g)
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5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

I understand that there is a difference when writing a Kc vs a Kp expression in terms of notation. While Kc uses brackets, [ ], it would be INCORRECT to write a Kp expression using brackets.

Yes, of course, I understand. I love chemistry.
No. What? I love physics. 
#chem4eva
#phys4neva

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Which of the following is TRUE? 
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A large value of K means that the equilibrium concentrations of products are large compared to the equilibrium concentrations of the reactants.
When the value of K is small, the equilibrium lies on the product side of the equilibrium reaction.
When the value of K is large, the equilibrium lies on the reactant side of the equilibrium reaction.
A small value of K means that the equilibrium concentrations of the reactants are small compared to the equilibrium concentrations of the products.

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

In which of the following cases will the LEAST time be required to arrive at equilibrium? K below refers to the equilibrium constant
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K is a very large number.
Cannot tell since the time to arrive at equilibrium does not depend on K.
K is about 1. 
K is a very small number. 

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