1.5 Volume of gas

Zn + 2HCI → ZnCI₂ + H₂. If 0.3 mol Zn used, and HCI is excess, what is amount of H₂ formed?

• 0.15 mol
• 0.3 mol
• 0.6 mol
• 1 mol

Zn +2HCI→ ZnCI₂ + H₂. If 0.3 mol Zn used, and HCI is excess, what is volume (cm³) of H₂ formed?

• 0.3 cm³
• 22700 cm³
• 6810 cm3
• 75666 cm³

Zn + 2HCI→ ZnCI₂ + H₂. If 3 mol HCI is used, Zn is in excess, what is amount of H₂ (mol) formed?

• 3 mol
• 1.5 mol
• 6 mol
• 1 mol

Zn + 2HCI → ZnCI₂ + H₂. If 3 mol HCI is used, Zn is in excess, what is volume of H₂ (cm³) formed?

• 1.5 cm³
• 22700 cm³
• 34050 cm³
• 15133 cm³

Mg + 2HCI → MgCI₂ + H₂. If 2 mol Mg used HCI is in excess, what is amount of H₂ formed?

• 1 mol
• 2 mol
• 4 mol
• 22700 mol

Mg + 2HCI → MgCI₂ + H₂. If 2 mol Mg used HCI is in excess, what is volume (cm³) of H₂ formed?

• 2 cm³
• 22700 cm³
• 45400 cm³
• 11350 cm³

Mg + 2HCI → MgCI₂ + H₂. If 0.03 mol HCI used, Mg is in excess, what is amount of H₂ formed?

• 0.015 mol
• 0.03 mol
• 0.06 mol
• 0.01 mol

Mg + 2HCI→MgCI₂ + H₂. If 0.03 mol HCI used, Mg in excess, what volume (cm³) H₂ formed?

• 0.015 cm³
• 22700 cm³
• 340.5 cm³
• 1513333 cm³

Mg + 2HCI→MgCI₂ + H₂. If 3 mol H₂ formed, how much Mg is used (mol), if HCI is in excess.

• 1 mol
• 3 mol
• 1.5 mol
• 2 mol

Mg + 2HCI→MgCI₂ + H₂. If 3 mol H₂ formed, how much HCI is used (mol), if Mg is in excess.

• 1 mol
• 3 mol 
• 1.5 mol
• 6 mol