[Algebra 2] Final Exam Review (Semester 2)

What is the base of the logarithm:
ln(8) = 2.08 ?

• e
• 10
• 2.08
• 8

Re-Write the Logarithm Equation into Exponential Form
log_xk = 7

• x⁷ = k
• 7^x = k
• x^k = 7
• 7^k = x

Re-Write the Exponential Equation into Logarithmic Form
e⁴ = 54.60

• 4 = ln (54.60) 
• ln (4) = 54.60
• 4 = log (54.60) 
• log (e) = 54.60

• log₈(a²/cb³)
• log₈(ca²/b³)
• log₈(a²cb³)
• log(a² − c − b³) 

Tags

CCSS.HSF.BF.B.5

CCSS.HSF.LE.A.4

• 5log₆(a) + 6log₆(c) − 30log₆(b)
• log₆(a) + 6log₆(c) − 5log₆(b)
• 6log₆(a) − 6log₆(c) − 30log₆(b)
• 6log₆(a) + 6log₆(c) − 30log₆(b)

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

• log (a⁵ + b²⁵)
• log (a⁵ − b²⁵)
• log (ab²⁵)
• log (a⁵/b²⁵)

Tags

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.B.5

CCSS.HSF.IF.C.8

Solve the Equation

• n = -1.12
• n = -1.16
• n = -0.64
• n = -2.10

Solve the Equation

• k = 3.39
• k = 2.60
• k = 2.58
• k = 3.02

Solve the Equation

• n = -1.44
• n = 12
• n = -8
• n = -4

Solve the Equation

• x = 0.76
• x = 23.30
• x = 0.91
• x = 3.46