Trigonometry (Intermediate)

Trigonometry (Intermediate)

11th - 12th Grade

10 Qs

quiz-placeholder

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Trigonometry (Intermediate)

Trigonometry (Intermediate)

Assessment

Quiz

Mathematics

11th - 12th Grade

Hard

Created by

Mr Tsoi-a-Sue

Used 6+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following graphs represent the function  f(x)=cos(2x)f\left(x\right)=\cos\left(2x\right) ?

Media Image
Media Image
Media Image
Media Image

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is true?

Sine is positive in the first and third quadrants.

Cosine is negative in the first and fourth quadrants.

Tangent is negative in the second and fourth quadrants.

Sine is negative in the second and third quadrants.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Calculate the value(s) of  θ\theta such that  cos(θ)=12\cos\left(\theta\right)=-\frac{1}{2} for  0θ2π0\le\theta\le2\pi .  

 θ=2π3,4π3\theta=\frac{2\pi}{3},\frac{4\pi}{3}  

 θ=π3,2π3\theta=\frac{\pi}{3},\frac{2\pi}{3}  

 θ=2π3\theta=\frac{2\pi}{3}  

 θ=π3,5π3\theta=\frac{\pi}{3},\frac{5\pi}{3}  

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Calculate the value(s) of  θ\theta such that  tan(2θ)=3\tan\left(2\theta\right)=\sqrt{3}  for  0θ2π0\le\theta\le2\pi 

 θ=π6,2π3\theta=\frac{\pi}{6},\frac{2\pi}{3}  

 θ=π6,2π3, 7π6,6π5\theta=\frac{\pi}{6},\frac{2\pi}{3},\frac{\ 7\pi}{6},\frac{6\pi}{5}  

 θ=π3,4π3, 7π3,12π5\theta=\frac{\pi}{3},\frac{4\pi}{3},\frac{\ 7\pi}{3},\frac{12\pi}{5}  

 θ= 7π6,6π5\theta=\frac{\ 7\pi}{6},\frac{6\pi}{5}  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve the equation 2sin(θ)=tan(θ)2\sin\left(\theta\right)=\tan\left(\theta\right) for  0θ3600^{\circ}\le\theta\le360^{\circ} 
Note: Use the fact that tan(θ)=sin(θ)cos(θ)\tan\left(\theta\right)=\frac{\sin\left(\theta\right)}{\cos\left(\theta\right)} .

 θ=0,30,90,150,180\theta=0^{\circ},30^{\circ},90^{\circ},150^{\circ},180^{\circ}  

 θ=0,180,360\theta=0^{\circ},180^{\circ},360^{\circ}  

 θ=0,60,180,300,360\theta=0^{\circ},60^{\circ},180^{\circ},300^{\circ},360^{\circ}  

 θ=0,300\theta=0^{\circ},300^{\circ}  

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For 0θ3600^{\circ}\le\theta\le360^{\circ} , solve  6cos2(θ)+6cos(θ)1=06\cos^2\left(\theta\right)+6\cos\left(\theta\right)-1=0 

 θ=81.6,120,240,278.4\theta=81.6^{\circ},120^{\circ},240^{\circ},278.4^{\circ}  

 θ=81.6,120\theta=81.6^{\circ},120^{\circ}  

 θ=240,120\theta=240^{\circ},120^{\circ}  

 θ=81.6, 278.4\theta=81.6^{\circ},\ 278.4^{\circ}  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Solve the equation sin2(θ)+3cos(2θ)=2\sin^2\left(\theta\right)+3\cos\left(2\theta\right)=2 for  0θ360°0\le\theta\le360\degree^{ } . Give your answer(s) to 1 decimal place.  
Note: Use the fact that  cos(2θ)=12sin2(θ)\cos\left(2\theta\right)=1-2\sin^2\left(\theta\right)  

 θ=153.4\theta=153.4^{\circ}  

 θ=26.6\theta=26.6^{\circ}  

 θ=26.6,153.4\theta=26.6^{\circ},153.4^{\circ}  

 θ=26.6,153.4,206.6,333.4\theta=26.6^{\circ},153.4^{\circ},206.6^{\circ},333.4^{\circ}  

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