2019.11/21栄道場~微分係数&導関数~

2019.11/21栄道場~微分係数&導関数~

11th Grade

6 Qs

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2019.11/21栄道場~微分係数&導関数~

2019.11/21栄道場~微分係数&導関数~

Assessment

Quiz

Mathematics

11th Grade

Practice Problem

Hard

Created by

Sakae Yokoyama

Used 4+ times

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6 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

関数f(x)f\left(x\right)  x=ax=a  における

微分係数 f(a)f'\left(a\right)  の定義は? 

 limh0  f(a+h)f(a)(a+h)a\lim_{h\rightarrow0\ }\ \frac{f\left(a+h\right)-f\left(a\right)}{\left(a+h\right)-a}  

 limh0  f(a+h)f(h)(a+h)h\lim_{h\rightarrow0}\ \ \frac{f\left(a+h\right)-f\left(h\right)}{\left(a+h\right)-h}  

 lima0  f(a+h)f(a)(a+h)a\lim_{a\rightarrow0}\ \ \frac{f\left(a+h\right)-f\left(a\right)}{\left(a+h\right)-a}  

 lima0  f(a+h)f(h)(a+h)h\lim_{a\rightarrow0}\ \ \frac{f\left(a+h\right)-f\left(h\right)}{\left(a+h\right)-h}  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

関数 f(x)f\left(x\right)  から定義にしたがって、

導関数 f(x)f'\left(x\right)  をもとめると?

 limh0  f(x+h)f(x)(x+h)x\lim_{h\rightarrow0\ }\ \frac{f\left(x+h\right)-f\left(x\right)}{\left(x+h\right)-x}  

 limh0  f(x+h)f(h)(x+h)h\lim_{h\rightarrow0}\ \ \frac{f\left(x+h\right)-f\left(h\right)}{\left(x+h\right)-h}  

 limx0  f(x+h)f(x)(x+h)x\lim_{x\rightarrow0}\ \ \frac{f\left(x+h\right)-f\left(x\right)}{\left(x+h\right)-x}  

 limx0  f(x+h)f(h)(x+h)h\lim_{x\rightarrow0}\ \ \frac{f\left(x+h\right)-f\left(h\right)}{\left(x+h\right)-h}  

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 y=2x4y=-2x^4   を微分せよ。

 y =8x3y\ '=-8x^3  

 y =6x4y\ '=-6x^4  

 y =8x4y\ '=-8x^4  

 y =8x5y\ '=-8x^5  

 y =6x3y\ '=-6x^3  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 y=2x3+6x+12y=2x^3+6x+12   を微分せよ。

 y =6x2+6y\ '=6x^2+6  

 y =6x3+6x2+12xy\ '=6x^3+6x^2+12x  

 y =2x2+6y\ '=2x^2+6  

 y =6x2+6x+12y\ '=6x^2+6x+12  

 y =2x3+6xy\ '=2x^3+6x  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

関数 f(x)=13x3+4xf\left(x\right)=\frac{1}{3}x^3+4x  について、

導関数 f (x)f\ '\left(x\right)  を求めよ。    

 f (x)=x2+4f\ '\left(x\right)=x^2+4  

 f (x)=x3+4xf\ '\left(x\right)=x^3+4x  

 f (x)=x4+4x2f\ '\left(x\right)=x^4+4x^2  

 f (x)=x2+4xf\ '\left(x\right)=x^2+4x  

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

関数 f(x)=13x3+4xf\left(x\right)=\frac{1}{3}x^3+4x  について、
微分係数 f (2)f\ '\left(-2\right)  を求めよ。  

    ヒント: f (x)=x2+4f\ '\left(x\right)=x^2+4  

16

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