Area Under Curve

Area Under Curve

11th - 12th Grade

30 Qs

quiz-placeholder

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Area Under Curve

Area Under Curve

Assessment

Quiz

Mathematics

11th - 12th Grade

Practice Problem

Hard

CCSS
HSA.REI.D.10, HSG.GMD.A.1, HSF.IF.B.4

+10

Standards-aligned

Created by

Barbara Dimberg

Used 14+ times

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30 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What statement best describes the Riemann Sum?

4 intervals, with heights using middle values

4 intervals, with heights using left values

5 intervals, with heights using middle values

5 intervals, with heights using right values

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the approximate area under the curve, using 4 intervals with heights using left values?

20

14

10

8

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What is the approximate area under the parabola using 4 intervals with heights using right values?

6

10

11

20

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

1.5

1.1418

1.1

1.4914

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

35

40.625

32.1

41

6.

MULTIPLE SELECT QUESTION

2 mins • 1 pt

Media Image

$32,000

$31,662.50

3,166,250 cents

3,200,000 cents

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Sketch the function  g(x)=4+x3g\left(x\right)=4+\sqrt{x-3}  . Then approximate  A(g, 5x8)A\left(g,\ 5\le x\le8\right)  
 by both using six right endpoint rectangles and six left endpoint rectangles. Write both of the sums using sigma notation.

Left endpoint:  12n=16(4+(0.5n+5)3)17.771\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.771  

Right endpoint: 12n=05(4+(0.5n+5)3)17.360\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.360  

Left endpoint:  12n=05(4+(0.5n)3)17.360\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.360  
Right endpoint:  12n=16(4+(0.5n)3)17.771\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.771  

Left endpoint:  12n=05(4+(0.5n+5)3)17.360\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.360 

Right endpoint:  12n=16(4+(0.5n+5)3)17.771\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n+5\right)-3}\right)\approx17.771  

Left endpoint:  12n=16(4+(0.5n)3)17.360\frac{1}{2}\sum_{n=1}^6\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.360  
Right endpoint:  12n=05(4+(0.5n)3)17.771\frac{1}{2}\sum_{n=0}^5\left(4+\sqrt{\left(0.5n\right)-3}\right)\approx17.771  

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