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Bacalaureat - Subiectul 2 (Legi de compozitie)

Authored by Nicolae Popa

Mathematics

12th Grade

Used 26+ times

Bacalaureat - Subiectul 2 (Legi de compozitie)
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15 questions

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1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie legea de corespondenta x o y = xy  -  x  -  y  + 2 Precizati elementul neutru pe multimea  G =[1;]G\ =\left[1;\infty\right]  

e = 1

e = 2

e = 0

e = 7

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie legea de corespondenta     x o y = xy x y +2\ x\ o\ y\ =\ xy\ -x\ -y\ +2  . Calculati  1o2o........o101o2o........o10  

e = 1

e = 2

e = 37

e = 10

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie legea de corespondenta     x o y = xy 4x 4y +20\ x\ o\ y\ =\ xy\ -4x\ -4y\ +20  . Calculati  x o x o x = xx\ o\ x\ o\ x\ =\ x  in multimea numerelor reale.

1 si 4

4 si 5

1 si 5

1

4.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie multimea.  G = (7; )G\ =\ \left(7;\ \infty\right) si  legea de corespondenta     x o y = xy 7x 7y +56\ x\ o\ y\ =\ xy\ -7x\ -7y\ +56  . Calculati simetricul lui 9.

e = 7

e = 7,5

e = 9

e = 10,25

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Pe  multimea   G =(1;)G\ =\left(1;\infty\right)  se defineste legea de corespondenta     x o y = x2 y2  x2  y2 +2 \ x\ o\ y\ =\ \sqrt{x^{2\ }y^2\ -\ x^2\ —\ y^2\ +2\ }  . Calculati elementul neutru.

e = 3

e = 0

e = 2

e = 1

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Pe  multimea   G =[1;]G\ =\left[1;\infty\right]  se defineste legea de corespondenta     x o y = x2 y2  x2  y2 +2 \ x\ o\ y\ =\ \sqrt{x^{2\ }y^2\ -\ x^2\ —\ y^2\ +2\ }  . Calculati  1 o 2 o 3 o 4 o .......o 1001\ o\ 2\ o\ 3\ o\ 4\ o\ .......o\ 100  

e = 50

e = 100

e = 2

e = 1

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Pe  multimea   G =[1;]G\ =\left[1;\infty\right]  se defineste legea de corespondenta     x o y = x2 y2  x2  y2 +2 \ x\ o\ y\ =\ \sqrt{x^{2\ }y^2\ -\ x^2\ —\ y^2\ +2\ }  . Aflati valoarea lui x care verifica relatia  x o x o x o x = xx\ o\ x\ o\ x\ o\ x\ =\ x  

e = 0

e = 1

e = 2

e = -1

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