Find the remaining trig ratios if sin ⁡ θ = 2 3 \sin\theta=\frac{2}{3} sin θ = 3 2

cos ⁡ θ = 5 3 tan ⁡ θ = 2 5 5 csc ⁡ θ = 3 2 sec ⁡ θ = 3 5 5 cot ⁡ θ = 5 2 \cos\theta=\frac{\sqrt{5}}{3}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{3\sqrt{5}}{5}\cot\theta=\frac{\sqrt{5}}{2} cos θ = 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> tan θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> csc θ = 2 3 sec θ = 5 3 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cot θ = 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

cos ⁡ θ = 5 7 tan ⁡ θ = 2 5 \cos\theta=\frac{5}{7}\ \tan\theta=\frac{2}{5} cos θ = 7 5 tan θ = 5 2 csc ⁡ θ = 3 2 sec ⁡ θ = 7 5 cot ⁡ θ = 5 2 \csc\theta=\frac{3}{2}\ \sec\theta=\frac{7}{5}\ \cot\theta=\frac{5}{2} csc θ = 2 3 sec θ = 5 7 cot θ = 2 5

cos ⁡ θ = 2 5 5 tan ⁡ θ = 2 3 \cos\theta=\frac{2\sqrt{5}}{5}\ \tan\theta=\frac{2}{3} cos θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> tan θ = 3 2 csc ⁡ θ = 3 2 sec ⁡ θ = 5 2 cot ⁡ θ = 3 2 \csc\theta=\frac{3}{2}\ \sec\theta=\frac{\sqrt{5}}{2}\ \cot\theta=\frac{3}{2} csc θ = 2 3 sec θ = 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cot θ = 2 3

cos ⁡ θ = 5 2 tan ⁡ θ = 2 5 5 csc ⁡ θ = 3 2 sec ⁡ θ = 2 5 5 cot ⁡ θ = 5 5 2 \cos\theta=\frac{\sqrt{5}}{2}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{2\sqrt{5}}{5}\cot\theta=\frac{5\sqrt{5}}{2} cos θ = 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> tan θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> csc θ = 2 3 sec θ = 5 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z"> cot θ = 2 5 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

Reciprocal Trig Functions and Applying Trig Functions

Authored by Kelsey Johnson

Mathematics

9th Grade - University

CCSS covered

Used 60+ times

Reciprocal Trig Functions and Applying Trig Functions

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10 questions

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MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Write all six trig ratios.

$\sin\theta=\frac{24}{25}\ \cos\theta=\frac{7}{25}\ \tan\theta=\frac{24}{7}\$ $\csc\theta=\frac{25}{24}\ \sec\theta=\frac{25}{7}\ \cot\theta=\frac{7}{24}$

$\sin\theta=\frac{7}{25}\ \cos\theta=\frac{24}{25}\ \tan\theta=\frac{7}{24}$ $\csc\theta=\frac{25}{7}\ \sec\theta=\frac{25}{24}\ \cot\theta=\frac{24}{7}$

Tags

CCSS.HSF.TF.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

$\cos\theta=\frac{5}{7}\ \tan\theta=\frac{2}{5}$ $\csc\theta=\frac{3}{2}\ \sec\theta=\frac{7}{5}\ \cot\theta=\frac{5}{2}$

$\cos\theta=\frac{2\sqrt{5}}{5}\ \tan\theta=\frac{2}{3}$ $\csc\theta=\frac{3}{2}\ \sec\theta=\frac{\sqrt{5}}{2}\ \cot\theta=\frac{3}{2}$

$\cos\theta=\frac{\sqrt{5}}{2}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{2\sqrt{5}}{5}\cot\theta=\frac{5\sqrt{5}}{2}$

$\cos\theta=\frac{\sqrt{5}}{3}\ \tan\theta=\frac{2\sqrt{5}}{5}\csc\theta=\frac{3}{2}\ \sec\theta=\frac{3\sqrt{5}}{5}\cot\theta=\frac{\sqrt{5}}{2}$

Tags

CCSS.HSG.SRT.C.6

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing side. Round answers to the nearest tenth.

39.4

12.2

29.1

Tags

CCSS.HSG.SRT.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing side. Round answers to the nearest tenth.

2.6

6.7

13.7

5.4

Tags

CCSS.HSG.SRT.C.8

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing angle. Round answers to the nearest whole degree.

$50\degree$

$40\degree$

$1\degree$

$33\degree$

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

CCSS.HSG.CO.C.10

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the missing angle. Round answers to the nearest whole degree.

$64\degree$

$35\degree$

$51\degree$

$63\degree$

Tags

CCSS.HSG.SRT.C.8

CCSS.HSG.SRT.C.6

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.D.11

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

What is the reciprocal function to sin?

sec

cos

csc

cot

Tags

CCSS.HSF.TF.A.2

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If $\sec\theta=\frac{29}{20}$ , then what is the hypotenuse?

Tags

CCSS.HSG.SRT.C.8

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Reciprocal Trig Functions and Applying Trig Functions

Write all six trig ratios.

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

Find the missing side. Round answers to the nearest tenth.

Find the missing side. Round answers to the nearest tenth.

Find the missing angle. Round answers to the nearest whole degree.

Find the missing angle. Round answers to the nearest whole degree.

What is the reciprocal function to sin?

What is the reciprocal function of sec?

What is the reciprocal function of tan?

If $\sec\theta=\frac{29}{20}$ , then what is the hypotenuse?

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Reciprocal Trig Functions and Applying Trig Functions

Write all six trig ratios.

Find the remaining trig ratios if sin⁡θ=23\sin\theta=\frac{2}{3}sinθ=32​

Find the missing side. Round answers to the nearest tenth.

Find the missing side. Round answers to the nearest tenth.

Find the missing angle. Round answers to the nearest whole degree.

Find the missing angle. Round answers to the nearest whole degree.

What is the reciprocal function to sin?

What is the reciprocal function of sec?

What is the reciprocal function of tan?

If sec⁡θ=2920\sec\theta=\frac{29}{20}secθ=2029​ , then what is the hypotenuse?

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

Find the remaining trig ratios if $\sin\theta=\frac{2}{3}$

If $\sec\theta=\frac{29}{20}$ , then what is the hypotenuse?