Logaritmska funkcija, jednadžbe i nejednadžbe

Logaritmska funkcija, jednadžbe i nejednadžbe

11th Grade

8 Qs

quiz-placeholder

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Logaritmska funkcija, jednadžbe i nejednadžbe

Logaritmska funkcija, jednadžbe i nejednadžbe

Assessment

Quiz

Mathematics

11th Grade

Hard

Created by

zrinka korbar

Used 28+ times

FREE Resource

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Graf na slici prikazuje funkciju

f(x)=(0.5)x1f\left(x\right)=\left(0.5\right)^x-1

f(x)=0.5(x1)f\left(x\right)=0.5^{\left(x-1\right)}

f(x)=log0.5x1f\left(x\right)=\log_{0.5}x-1

f(x)=log0.5(x1)f\left(x\right)=\log_{0.5}\left(x-1\right)

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Graf na slici prikazuje funkciju

f(x)=log2x2f\left(x\right)=\log_2x-2

log2(x+2)\log_2\left(x+2\right)

f(x)=log2(x+2)+1f\left(x\right)=\log_2\left(x+2\right)+1

f(x)=log2(x+2)1f\left(x\right)=\log_2\left(x+2\right)-1

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 log3(3x8)=2x\log_3\left(3^x-8\right)=2-x  

x=9

x=2

x=9, x=-1

x=-9, x=-1

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Rješenje jednadžbe je log[3+2log(x+1)]=1\log\left[3+2\log\left(x+1\right)\right]=1  

x=0.9

x=-0.9

x=1.1

x=-1.1

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Temperatura hlađenja nekog tijela dana je formulom , 

 T(t)=25+55e0.061tT\left(t\right)=25+55e^{-0.061t}  , gdje je t vrijeme u minutama. Kada će temperatura tijela biti 45°C?

za 16 minuta

za 16.5 minuta

za 16.6 minuta

za 1.66 minuta

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Rješenje nejednadžbe  log3(2x+1)<2\log_3\left(2x+1\right)<2  je interval:


 <0.5, 4><-0.5,\ 4>  

 [0.5,4]\left[-0.5,4\right]  

 <0.5,4><0.5,4>  

 [0.5,4 ]\left[0.5,4\ \right]  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Rješenje nejednadžbe  log0.25(12x)>0\log_{0.25}\left(1-2x\right)>0  je interval:

 <,0.5><-\infty,0.5>  

 <0.5,><0.5,\infty>  

 <0, 0.5><0,\ 0.5>  

 <0.5, 0><-0.5,\ 0>  

8.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Rješenja jednadžbe 2+logy2logy=3logy\frac{2+\log y}{2-\log y}=3\log y  su

 y1=1, y2=23y_1=1,\ y_2=\frac{2}{3}  

 y1=10, y2=1023y_1=10,\ y_2=10^{\frac{2}{3}}  

 y1=1, y2=23y_1=-1,\ y_2=-\frac{2}{3}  

 y1=10, y2=10y_1=10,\ y_2=\sqrt{10}