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Descompunerea unui vector într-un reper cartezian

Authored by Andreea Țui

Mathematics

9th Grade

Used 8+ times

Descompunerea unui vector într-un reper cartezian
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9 questions

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1.

FILL IN THE BLANKS QUESTION

2 mins • 1 pt

Fie punctele

 A(3, 1)A\left(3,\ -1\right)   și  B(1, 4)B\left(-1,\ -4\right)  Lungimea segmentului AB este egală cu:



(a)  

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie  A(1,3)A\left(1,3\right)  și  B(2,5)B\left(-2,5\right)  . Descompunerea vectorului  AB\overrightarrow{AB}  este: 


 3i+8j3\overrightarrow{i}+8\overrightarrow{j}  

 3i+2j-3\overrightarrow{i}+2\overrightarrow{j}  

 ij\overrightarrow{i}-\overrightarrow{j}  

 i+j\overrightarrow{i}+\overrightarrow{j}  

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie   A(2,5)A\left(2,5\right)   și   B(6,7)B\left(6,-7\right)  Calculați coordonatele mijlocului segmentului AB. 


 (8,2)\left(8,-2\right)  

 (2,1)\left(-2,-1\right)  

 (4,1)\left(4,-1\right)  

 (1,1)\left(1,1\right)  

4.

FILL IN THE BLANKS QUESTION

5 mins • 1 pt

Fie   A(1,2), B(1,6), C(5, 8).A\left(1,2\right),\ B\left(-1,6\right),\ C\left(5,\ -8\right).  Distanța de la punctul C la mijlocul segmentului AB este: 



(a)  

5.

FILL IN THE BLANKS QUESTION

3 mins • 1 pt

Aflați m știind că vectorii u=3i+mj  \overrightarrow{u}=3\overrightarrow{i}+m\overrightarrow{j}\ \    și  v=2i+16j\overrightarrow{v}=2\overrightarrow{i}+16\overrightarrow{j}  sunt coliniari.




(a)  

6.

FILL IN THE BLANKS QUESTION

3 mins • 1 pt

Aflați m știind că vectorii  u=2i+mj\overrightarrow{u}=2\overrightarrow{i}+m\overrightarrow{j}   și  v=7i+(3m1)j\overrightarrow{v}=7\overrightarrow{i}+\left(3m-1\right)\overrightarrow{j}   sunt coliniari.




(a)  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Fie  u=2i5j\overrightarrow{u}=2\overrightarrow{i}-5\overrightarrow{j}  și  v=5i+3j\overrightarrow{v}=-5\overrightarrow{i}+3\overrightarrow{j}  Calculați  uv\overrightarrow{u}-\overrightarrow{v}  


 5ij5\overrightarrow{i}-\overrightarrow{j}  

 i+2j\overrightarrow{i}+2\overrightarrow{j}  

 i2j\overrightarrow{i}-2\overrightarrow{j}  

 7i8j7\overrightarrow{i}-8\overrightarrow{j}  

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