ALG1B 5.8 Point-Slope Form

Which equation is the point-slope form?

• $y-y_1=m\left(x-x_1\right)$

• $y=mx+b$

• $Ax+By=C$

Write an equation in point-slope form for the line with   $Slope=\frac{1}{2}\ and\ point\ \left(6,\ -2\right)$  

 $y-y_1=m\left(x-x_1\right)$  

•  $y-6=\frac{1}{2}\left(x+2\right)$  

•  $y-2=\frac{1}{2}\left(x-6\right)$  

•  $y+2=\frac{1}{2}\left(x-6\right)$  

•  $y+2=\frac{1}{2}\left(x+6\right)$  

Write an equation in point-slope form for the line with
 $slope=-4\ and\ point\ \left(-1,\ 5\right)$  

•  $y-4=-1\left(x-5\right)$  

•  $y-1=-4\left(x-5\right)$  

•  $y-5=-4\left(x-1\right)$  

•  $y-5=-4\left(x+1\right)$  

 $y-3=2\left(x+5\right)$  

To graph a line given in point-slope form, you need to pick out the point and the slope from the equation. Find the slope and point on the line from the equation shown.

•  $slope=2,\ point\ is\ \left(3,\ 5\right)$  

•  $slope=2,\ point\ is\ \left(-5,\ 3\right)$  

•  $slope=2,\ point\ is\ \left(-5,\ -3\right)$  

•  $slope=2,\ point\ is\ \left(5,\ 3\right)$  

Write the equation that describes the line in slope-intercept form (y = mx + b).

 $slope=2,\ \left(-3,\ 6\right)\ is\ on\ the\ line$  

•  $y=2x+12$  

•  $y=2x+9$  

•  $y=2x+3$  

•  $y=2x$  

Write the equation that describes the line in slope-intercept form (y = mx + b).

 $\left(2,-5\right)\ and\ \left(-1,7\right)\ are\ on\ the\ line$  

•  $y=4x+3$  

•  $y=4x-3$  

•  $y=-3x-4$  

•  $y=-4x+3$  

Write the equation that describes the line in slope-intercept form (y = mx + b).

x-intercept = -1 and y-intercept = 7

•  $y=7x-1$  

•  $y=-1x-7$  

•  $y=7x+7$  

•  $y=\frac{1}{7}x+7$