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LUYỆN TẬP TÍCH PHÂN

Authored by Như Quỳnh

Mathematics

12th Grade

Used 26+ times

LUYỆN TẬP TÍCH PHÂN
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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Tích phân

 I=∫01(3x2+2x−1)dxI=\int_0^1\left(3x^2+2x-1\right)dx  bằng

 I=1I=1  

 I=2I=2  

 I=3I=3  

 I=−1I=-1  

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Tích phân

 I=∫01(x+1)2dxI=\int_0^1\left(x+1\right)^2dx  bằng

 83\frac{8}{3}  

 22  

 73\frac{7}{3}  

 44  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Cho tích phân

 ∫12(3x3−x2−4x+1)dx\int_1^2\left(3x^3-x^2-4x+1\right)dx  có giá trị là


 −4712-\frac{47}{12}  

 4712\frac{47}{12}  

 1247\frac{12}{47}  

 7412\frac{74}{12}  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Tích phân

 I=∫0π6sin⁡2xdxI=\int_0^{\frac{\pi}{6}}\sin^2xdx  có giá trị là

 π12+38\frac{\pi}{12}+\frac{\sqrt{3}}{8}  

 π12−38\frac{\pi}{12}-\frac{\sqrt{3}}{8}  

 −π12+38-\frac{\pi}{12}+\frac{\sqrt{3}}{8}  

 π12−34\frac{\pi}{12}-\frac{\sqrt{3}}{4}  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Tích phân

 I=∫0π6sin⁡2xdxI=\int_0^{\frac{\pi}{6}}\sin^2xdx  có giá trị là

 π12+38\frac{\pi}{12}+\frac{\sqrt{3}}{8}  

 π12−38\frac{\pi}{12}-\frac{\sqrt{3}}{8}  

 −π12+38-\frac{\pi}{12}+\frac{\sqrt{3}}{8}  

 π12−34\frac{\pi}{12}-\frac{\sqrt{3}}{4}  

6.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Giả sử

 ∫15dx2x−1=ln⁡K\int_1^5\frac{dx}{2x-1}=\ln K  . Giá trị của K là

 99  

 88  

 8181  

 33  

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Cho

 I=∫116xdxI=\int_1^{16}\sqrt{x}dx  và  J=∫0π4cos⁡2xdxJ=\int_0^{\frac{\pi}{4}}\cos2xdx  . Khi đó

 I<JI<J  

 I>JI>J  

 I=JI=J  

 I>J>2I>J>2  

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