Precalculus Chapter 5 Review

Solve the following for cos²θ:
sin²θ + cos²θ = 1

• cos²θ = 1 - sin²θ
• cosθ = 1 + sin²θ
• cosθ = 1 - sinθ
• cos²θ = Adj/hyp

Tags

CCSS.HSF.TF.C.8

Rewrite tan(x) in terms of sin(x) and cos(x).

• tan(x) = cos(x)/sin(x)
• tan(x) = 1/cot(x)
• tan(x) = sin(x)/cos(x)
• tan(x) = opp/adj

Tags

CCSS.HSF.TF.C.8

Solve the following for tan²θ:
1 + tan²θ = sec²θ 

• tan²θ = sec²θ + 1
• tan²θ = sec²θ - 1
• tanθ = secθ - 1
• tan²θ = opp/adj

What is csc(x) equivalent to?

• 1/sin(x)
• 1/tan(x)
• sin(x)
• 1/cos(x)

Tags

CCSS.HSF.TF.A.4

Please select the correct solution

• csc² x
• cot² x
• sin² x
• sec² x

Please select the correct solution cos ² x + sin ² x=  

• 1
• csc ² x + sec ² x
• sin ² x
• 1 - sin ² x

Please select the correct solution

• csc x
• sec x
• cot x
• tan x

Simplify

• sin²θ
• cosθ
• tanθ
• 1- sin²θ

Simplify

• -1
• sin θ
• csc θ
• 1

Simplify

• csc²θ
• sec²θ
• cscθ
• 1