Distance Formula Unit 1 Test review

How is the distance formula correctly written:

• $d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\$

• $d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)^2}$

• $d\ =\ \sqrt{\left(y_{1\ }-\ y\ _2\right)^2\ +\ \left(x_{2\ }-\ x_1\right)}^2$

• d = $\sqrt{\left(x\right)^2-\ \left(y\right)^2}$

Tags

CCSS.HSG.GPE.B.7

A(3,1) B(-2,-1) written correctly is:

• $\sqrt{\left(-2-3\right)^2\ +\ \left(-1-1\right)^2}$

• $\sqrt{\left(1-3\right)^2\ +\ \left(-1-2\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$

Tags

CCSS.HSG.GPE.B.7

A(2,0) B(-2,4) is written as

• $d\ =\ \sqrt{\left(4-2\right)^2\ -\ \left(0-2\right)^2}$

• $d\ =\ \sqrt{\left(4-0\right)^2\ -\ \left(-2-2\right)^2}$

• $d\ =\ \sqrt{\left(-2\ +0\right)^2\ +\ \left(4+2\right)^2}$

• $d\ =\ \sqrt{\left(-2-2\right)^2\ +\ \left(4-0\right)^2}$

Tags

CCSS.HSG.GPE.B.7

What is the distance between AB

• 0

• 8

• 9

• 7

Tags

CCSS.HSG.GPE.B.7

What is the distance between AB?

• 0

• undefined

• 5

• 4

Tags

CCSS.HSG.GPE.B.7

How is AB written in the distance formula?

• 
  $d\ =\ \sqrt{\left(5-3\right)^2\ +\ \left(0--2\right)^2}$
  

• $d\ =\ \sqrt{\left(2-5\right)^2\ +\ \left(3\ -0\right)^2}$

• $d\ =\ \sqrt{\left(5-3\right)^2\ -\ \left(0--2\right)^2}$

• $d\ =\ \sqrt{\left(4-3\right)^2\ -\ \left(2-4\right)^2}$

Tags

CCSS.HSG.GPE.B.7

Find the distance between (-12, 1) and (12, -1).

• 24.05
• 24.06
• 24.07
• 24.08

Find the distance between (-5, -8) and (-1, -16).

• 8.9
• 9.8
• 10.3
• 11

Tags

CCSS.HSG.GPE.B.7

Find the distance between (3, 24) and (7, 56).

• 32.1
• 32.2
• 32.3
• 32.4

Tags

CCSS.HSG.GPE.B.7

Find the distance between (-4, 5) and (7, 18).

• 15.96
• 16.08
• 16.23
• 17.03

Tags

CCSS.HSG.GPE.B.7