Calculus I - Derivatives

Calculus I - Derivatives

University

5 Qs

quiz-placeholder

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Calculus I - Derivatives

Calculus I - Derivatives

Assessment

Quiz

Mathematics

University

Medium

Created by

Danphil Daniel

Used 1+ times

FREE Resource

5 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate the following function f(x)=(x5)(x2+1)f\left(x\right)=\left(x-5\right)\left(x^2+1\right)  

 f(x)=3x2+10x+1f'\left(x\right)=3x^2+10x+1  

 f(x)=4x2+3x+1f'\left(x\right)=4x^2+3x+1  

 f(x)=3x210x+1f'\left(x\right)=3x^2-10x+1  

 f(x)=3x210xf'\left(x\right)=3x^2-10x  

2.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate the following function h(t)=t42t2+7tt3h\left(t\right)=\frac{t^4-2t^2+7t}{t^3}  

 h(x)=1+2t2+14t3h'\left(x\right)=1+2t^2+14t^3  

 h(x)=1+2t214t3h'\left(x\right)=1+2t^{-2}-14t^{-3}  

 h(x)=2t214t3h'\left(x\right)=2t^{-2}-14t^{-3}  

 h(x)=1+t2t3h'\left(x\right)=1+t^{-2}-t^{-3}  

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate the function

  g(x)=x31x6+1x5g\left(x\right)=x^3-\frac{1}{x^6}+\frac{1}{\sqrt{x^5}}  

 g(x)=3x2+6x7+32x52g'\left(x\right)=3x^2+6x^{-7}+\frac{3}{2}x^{-\frac{5}{2}}  

 g(x)=3x2+6x7+52x72g'\left(x\right)=3x^2+6x^7+\frac{5}{2}x^{-\frac{7}{2}}  

 g(x)=3x2+6x752x72g'\left(x\right)=3x^2+6x^{-7}-\frac{5}{2}x^{-\frac{7}{2}}  

 g(x)=3x26x7+52x12g'\left(x\right)=3x^2-6x^7+\frac{5}{2}x^{-\frac{1}{2}}  

4.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate the following function f(x)=(x2x)(72x3)f\left(x\right)=\left(x-\frac{2}{x}\right)\left(7-2x^3\right)  

 f(x)=8x3+8x+14x2+7f'\left(x\right)=-8x^3+8x+\frac{14}{x^2}+7  

 f(x)=8x38x+14x+7f'\left(x\right)=8x^3-8x+\frac{14}{x^{ }}+7  

 f(x)=8x+14x2+7f'\left(x\right)=8x+\frac{14}{x^2}+7  

 f(x)=8x4+8x2+14x2+7f'\left(x\right)=-8x^4+8x^2+\frac{14}{x^2}+7  

5.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

Differentiate the following function V(x)=110t+t25t+2t3V\left(x\right)=\frac{1-10t+t^2}{5t+2t^3}  

 V(x)=2x4+40x3+x25(5x+2x3)2V'\left(x\right)=\frac{2x^4+40x^3+x^2-5}{\left(5x+2x^3\right)^2}  

 V(x)=2x440x3x25(5x+2x3)V'\left(x\right)=\frac{-2x^4-40x^3-x^2-5}{\left(5x+2x^3\right)^{ }}  

 V(x)=2x440x3+x2+5(5x+2x3)2V'\left(x\right)=\frac{-2x^4-40x^3+x^2+5}{\left(5x+2x^3\right)^2}  

 V(x)=2x4+40x3x25(5x+2x3)2V'\left(x\right)=\frac{-2x^4+40x^3-x^2-5}{\left(5x+2x^3\right)^2}